Suppose that a class contains 15 boys and 30 girls, and that 10 students are to be selected at random for a special assignment.
Find the probability that exactly 3 boys will be selected.
1 answer:
Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students
1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2
0.22×0.33×0.2=0.0148
1.48%
I'm not sure 100%... double check answer please
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Answer:
n=48
Step-by-step explanation:
n
_ = 1 6
3
Multiply each side by 3
n/3 * 3 = 16*3
n = 48
Answer:
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Step-by-step explanation:
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