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hichkok12 [17]
3 years ago
15

Someone help please 20 points

Mathematics
2 answers:
denis23 [38]3 years ago
3 0

Answer:

Whole number

Repeating decimal

mixed number

improper fraction

Terminating decimal

square root of a perfect square

brilliants [131]3 years ago
3 0
All of them are correct because all numbers are integers
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Need help plz I’m almost done
JulsSmile [24]

Hello!


The graph, (2/5)^x is an exponential function.


Since there is not a negative symbol in the front of the function, options A and B are incorrect.


For option 3 to be correct, there would need to be a negative symbol in front of the exponent, x.


So therefore, the answer option 4. (Also, I'll post a graph. :))


8 0
3 years ago
Henry draws an obtuse triangle how many obtuse angles does Henry's triangle have?
drek231 [11]

it would only have 1 obtuse angle

4 0
3 years ago
Read 2 more answers
If the length of rectangle is thrice of its breadth and it's perimeter is 32 cm then finds its area​.​
jeka57 [31]

Answer:

48 cm²

Explanation:

Let the breadth be b, then the length is 3b

P = 2(Length + Breadth)

32 = 2(3b + b)

32 = 2(4b)

8b = 32

b = 4

Breadth is 4 cm

Length: 3b = 3(4) = 12 cm

Area of rectangle:

Length × Breadth

12 × 4

48 cm²

3 0
2 years ago
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What is 1/3 out of 100%
Andrej [43]
The answer your looking for is 33.3%

(it goes on a lot longer but that's just rounded to 1 decimal place)
5 0
4 years ago
4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10
Andrew [12]

Given the function f(x);

f(x)=-4x^2+4x-1

Evaluating the function f(x+h);

\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}

So;

f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1

Evaluating the second function;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}

simplifying further;

\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}

Therefore, we have;

undefined

7 0
1 year ago
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