Answer:
I assume you know Arithmetic Progression .
so, we have to find the first and last 4-digit number divisible by 5
first = 1000 , last = 9990
we have a formula,
= a + (n-1)d
here,
is the last 4-digit number divisible by 5.
n is the number of 4-digit even numbers divisible by 5
d is the common difference between the numbers, which is 10 in this case
a is the first 4-digit number divisible by 5
9990 = 1000 + (n-1)*10
899 = n-1
n = 900
Hence, there are 900 4-digit even numbers divisible by 5
For b it is A,M and T
For C it is 0%
I think maybe either B or C, ope I helped, sorry if I didn't!!
Answer:
132 cm²
Step-by-step explanation:
Your welcome
Between 2 and 3, should be somewhere before .5