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UNO [17]
3 years ago
5

Is someone know the answer????????!!,?!, Thank you

SAT
1 answer:
mafiozo [28]3 years ago
5 0

Answer: 11. A. Receipt 12. A. Inflation 13. C. Investment 14. Expense

Explanation: Hope this helped! :)

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Suppose that the annual federal deficit is $350 billion. Gross domestic product 'gdp', a measure of the size of the economy is $
larisa86 [58]

Based on the information the ratio between the deficit and gdp as a percentage is 2.41%.

<h3>Ratio between the deficit and gdp:</h3>

Using this formula

Ratio between the deficit and gdp=Annual federal deficit/Gross domestic product×100

Where:

Annual federal deficit=$350 billion

Gross domestic product=$14,500 billion

Let plug in the formula

Ratio between the deficit and gdp=$350 billion/$14,500 billion×100

Ratio between the deficit and gdp=2.41%

Inconclusion the ratio between the deficit and gdp as a percentage is 2.41%.

Learn more about ratio between the deficit and gdp here:brainly.com/question/4731320

6 0
2 years ago
Study the table and give solution to the problem using the six steps.
faltersainse [42]
What table? you didn’t attach anything?
3 0
2 years ago
Need help right now please thank you
Elza [17]

Answer:

29 %

Explanation:

check the table for given condition and divide by total no of students

5 0
3 years ago
At 900 ∘c,kc=0. 0108 for the reaction caco3(s)←→cao(s)+co2(g) a mixture of caco3, cao, and co2 is placed in a 10. 0-l vessel at
Mrac [35]

The concentration of CaCO3 increases in all cases because Q> K.

<h3>What is equilibrium?</h3>

A chemical reaction is said to have attained equilibrium when the rate of forward reaction is equal to the rate of reverse reaction. We are told that the Kc of the reaction is 0. 0108.

In the first case:

CaCO3 - 15.0 g/100g/mol/10 L = 0.015 M

CaO - 15.0 g/56 g/mol/10 L = 0.027 M

CO2 - 4.25 g/44 g/mol / 10 L = 0.0096 M

Q = [0.027] [0.0096]/0.015

Q = 0.017

Since Q > K, the concentration of CaCO3 increases

In the second case;

CaCO3 -  2.5 g/100g/mol/10 L =0.0025 M

CaO - 25.0 g/56 g/mol/10 L = 0.045 M

CO2 - 5.66 g/44 g/mol / 10 L = 0.013 M

Q = [0.045 ] [ 0.013]/[0.0025 ]

Q = 0.23

Q > K the concentration of CaCO3 increases

In the third case;

CaCO3 - 30.5 g/100g/mol/10 L =0.031 M

CaO - 25.5 g/56 g/mol/10 L =0.046 M

CO2 - 6.48 g//44 g/mol / 10 L = 0.015 M

Q = [0.046] [ 0.015]/[0.031]

Q = 0.022

Q> K hence the concentration of CaCO3 increases

Missing parts: At 900oC, Kc = 0.0108 for the reaction: CaCO3(s) <===> CaO(s) + CO2(g) A mixture of CaCO3, CaO, and CO2 is placed in a 10.0 Liter vessel at 900oC. For the following mixtures, will the amount of CaCO3 increase, decrease, or remain the same as the system approaches equilibrium? CaCO3 CaO CO2 At Equilibrium, CaCO3 will ?? 15.0 g 15.0 g 4.25 g Answer 2.5 g 25.0 g 5.66 g Answer 30.5 g 25.5 g 6.48 g Answer

Learn more about equilibrium: brainly.com/question/17960050

4 0
2 years ago
Which of the following is typically not found on a prescription label:.
rewona [7]

Answer:

d

Explanation:

6 0
3 years ago
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