4 years ago

Multiply (2t^2-t-8)(2t^2+2t-1)

Mathematics

1 answer:

algol134 years ago

5 0

(2t^2−t−8)(2t^2+2t−1)

= (2t^2+−t+−8)(2t^2+2t+−1)

= (2t^2)(2t^2) + (2t^2)(2t) + (2t^2)(−1) + (−t)(2t^2) + (−t)(2t) + (−t)(−1) + (−8)(2t^2) + (−8)(2t) + (−8)(−1)

=4t^4+4t^3−2t^2−2t^3−2t^2+t−16t^2−16t+8

=4t^4+2t^3−20t^2−15t+8

Sorry if I made it too complicated

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