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My name is Ann [436]
3 years ago
11

What is the nearest integer to 4.18 divided by 0.68?

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0
4.18/0.68=6.147058824 this is the answer of your questions
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Please help!! 10 point available:)
salantis [7]

Answer:

1) - 2n + 14

2)- 5n + 30

Step-by-step explanation:

n = a + (n - 1) \times d \\  = 12 + (n - 1) \times  - 2 \\  = 12  - 2n + 2 \\  =  - 2n + 14

n = a + (n - 1) \times d \\  = 25 + (n - 1) \times  - 5 \\  = 25 - 5n + 5 \\  =  - 5n + 30

<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>

8 0
3 years ago
Which expression is equivalent to x-3x-(-5x)?
Katena32 [7]

Answer:

D

Step-by-step explanation:

x-3x-(-5x)=-2x+5x=3x

4 0
3 years ago
Read 2 more answers
Is 4/9 half of 8/18 ?
elixir [45]
Divide by 2 and find out.

4/9 / 2

Multiply by its reciprocal:

4/9 * 1/2

Multiply the numerators and denominators together:

4/18

4/18 does not equal 8/18, so 4/9 isn't half of 8/18.
5 0
3 years ago
Read 2 more answers
PLS HELP :(
faust18 [17]

Answer: 47.1

Step-by-step explanation:

1/3πr^2h

=1/3×π×32×5

=15π

= 47.123889803847 feet3

4 0
3 years ago
Read 2 more answers
200 σ j=1 2j( j 3) describe the steps to evaluate the summation. what is the sum?
ziro4ka [17]

The sum of the equation is  = 5494000.

<h3>What does summation mean in math?</h3>

The outcome of adding numbers or quantities mathematically is a summation, often known as a sum. A summation always has an even number of terms in it. There may be just two terms, or there may be 100, 1000, or even a million. Some summations include an infinite number of terms.

<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

The sum is 5,494,000.

<h3>Calculation according to the statement:</h3>

\sum_{j=1}^{200} 2 j(j+3)

simplifying them we get:

\sum_{j=1}^{200} 2 j^{2}+6 j

Split the summation into smaller summations that fit the summation rules.

\sum_{j=1}^{200} 2 j^{2}+6 j=2 \sum_{j=1}^{200} j^{2}+6 \sum_{j=1}^{200} j

\text { Evaluate } 2 \sum_{j=1}^{200} j^{2}

The formula for the summation of a polynomial with degree 2

is:

\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}

Substitute the values into the formula and make sure to multiply by the front term.

(2)$$\left(\frac{200(200+1)(2 \cdot 200+1)}{6}\right)$$

we get: 5373400

Evaluating same as above : 6 \sum_{j=1}^{200} j

we get: 120600

Add the results of the summations.

5373400 + 120600

= 5494000

The sum of the equation is  = 5494000.

To know more about  summations visit:

brainly.com/question/16679150

#SPJ4

6 0
2 years ago
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