Answer:
Step-by-step explanation:
Given that
A sample space consists of five simple events, E1, E2, E3, E4, and E5.
a If P(E1) = P(E2) = 0.15,
P(E3) = 0.4, and P(E4) = 2P(E5),
We know that total probability =1
i.e. sum of probabilities of All Eis would be 1
where x = P(E5)
Solving for x we get
x=0.30
So P(E4) = 0.2 and P(E5) = 0.1
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b) Let P(E3) =P(E4) = P(E5) = y
then we have
total probability = 
Probability of remain are 0.2 each.
Answer:
All real values, (-∞, ∞)
Step-by-step explanation:
<u>Step 1: Distribute</u>
5y + (86 - y) = 86 + 4y
5y + 86 - y = 86 + 4y
<u>Step 2: Combine like terms</u>
5y + 86 - y = 86 + 4y
4y + 86 = 86 + 4y
<u>Step 3: Subtract 4y from both sides</u>
4y + 86 - 4y = 86 + 4y - 4y
86 = 86
<u>Step 4: Subtract 86 from both sides</u>
0 = 0
Answer: All real values, (-∞, ∞)
Answer: 16/25 (sorry I'm not really sure bc I'm just a middle schooler)
Step-by-Step explanation:
2 2/5 km=2.4 kilometers
3 3/4 minutes=3.75 minutes
2.4/3.75=240/375
240/375=48/75=16/25=64/100=0.64
0.64 km/minute (0.64 km per minute)
you can solve the problem using the fractions...
2 2/5=12/5
3 3/4=15/4
(12/5)/(15/4)=(12/5)*(4/15)=48/75=16/25=0.64 again, or you can simplify before multiplying...
(12/5)/(15/4)=(12/5)*(4/15)=(4/5)*(4/5)=16/25...
answer:
Step-by-step explanation:
Solving for part A
Domain of composition: x ≠ 0 i.e. Domain is the set of "Real numbers excluding number 0".
Solving for part B
