Answer:
Step-by-step explanation:
PART 1
y=mx+b
m is slope and slope is 0 sooo
y=0x+b
it passes through (3,7)
7=0(3)+b
7=0+b
b=7
y=0x+7
so just y=7
PART 2
y=mx+b
y=1/5x+b
1/2=1/5(-2/3)+b
1/2=-2/15+b
1/2+2/15=b
15/30+4/30=b
19/30=b
y=1/5x+19/30
A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
Learn more about translation rule:
brainly.com/question/15161224
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The answer is the Parallelogram
Two point zero one hundred twenty
√129 is less than 
.
Let us first solve for √129.
➝
➝
Now,
➝
➝
Clearly,
➵
➵
Hence, √129 is less than 
.
