Answer:
The seats in the lower section are x= 1720 , in the upper section are 3x= 5160 and y=24,200 - 4x= 24,200 - 6880= 17320 tickets in the field.
Step-by-step explanation:
Let x represent the number of seats in the lower section then the number of seats in the upper section is 3x and y the number of seats in the field.
The equation can be written as
80x + 60 (3x) + 40 y= $1,140,000-----1
And x+ 3x+ y= 24,200------2
4x+ y= 24,200
or y= 24,200-4x----3
Solving Eq 1
80x + 180x + 40 y= $1,140,000
260x+ 40 y=$1,140,000-----4
<em><u>Putting Eq 3 in Eq 4</u></em>
260x+ 40 y=$1,140,000
260x+ 40(24,200-4x-)=$1,140,000
260x + 968,000- 160x= $1,140,000
100x= $1,140,000-968,000
100x= 172,000
x= 1720
The seats in the lower section are x= 1720 , in the upper section are 3x= 5160 and y=24,200 - 4x= 24,200 - 6880= 17320 tickets in the field.
Putting the values of x and y in Eq 1 we get the same revenue.
80x + 60 (3x) + 40 y= $1,140,000
80(1720) + 60 (5160) + 40( 17320)= $1,140,000
137600 + 309600 + 692800= $1,140,000
137600 + 1002400= $1,140,000