Question

(2n²+15n-18)÷(n+9)a) 2n-3, R 9b)2n-1, R 4c)2n-6, R 6d)2n-3, R 11​

Answer 1

Answer:

The answer is A

Step-by-step explanation:

This is polynomial division and the concept is pretty easy

The first thing to do is what can I multiply by n to get $2n^{2}$

The reason for this is so that when subtraction is done, the $n^{2}$ coefficient becomes zero. That will be 2n

Next we multiply 2n through (n+9)

we do the addition and $n^{2}$  is cancelled and we get 18n.

Now, we do 15n - 18n = -3n

we pull down -18  to get -3n-18

Next we have to multiply through by -3 so that when subtraction is done, the coefficient of n becomes zero

Doing that, coefficient of n cancels out and we have -18 - (-27) = 9

which is the remainder.

Consider the picture attached to this solution for better illustration

Answer 2

Answer:

a) 2n-3, R 9

Step-by-step explanation:

(2n²+15n-18) = (2n²+15n-27) + 9 = (n+9) (2n-3) + 9