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xz_007 [3.2K]
4 years ago
6

Solve: The quantity 2 x minus 20 divided by 3 = 2x

Mathematics
1 answer:
Arisa [49]4 years ago
7 0
The answer is
<span>2 x minus 20 divided by 3 = 2x
equivalent of  </span><span>
</span>(2 x -20) / 3 = 2x for solving it, <span><span>(2 x -20) = 2x . (3) is sufficient
</span> </span>
so <span>2 x -20 = 6x   </span><span> -20 = 6x - </span><span>2 x and  -20 = 4x so x = -5</span>




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River rambler charges $25 per day to rent a kayak. How much will it cost to rent a kayak for 5 days? Write and solve an equation
Sati [7]

Answer:

C=25d

Step-by-step explanation:

We write an equation where C or cost is my output and d or days is my input. I should be able to put in any number of days and find the cost. Let's gather some data:

River Ramble

Day 1 $25(1)=25 cost

Day 2 $25(2)=50 cost

Day 3 $25(3)=75 cost

Day d $25(d)=C.

Our equation is C=25d.

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4 years ago
The high temperature in Rockport over the weekend was 55 1/4 °F. Write this as a decimal
Hoochie [10]
55.25 °F
I believe this is right
6 0
3 years ago
A student claims that 2i is the only imaginary root of a polynomial equation that has real coefficients. Explain the student's m
____ [38]

Answer:

The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i

Step-by-step explanation:

1) This claim is mistaken.

2) The Fundamental Theorem of Algebra assures that any polynomial  f(x)=0 whose degree is n ≥1 has at least one Real or Imaginary root. So by the Theorem we have infinitely solutions, including imaginary roots ≠ 2i with real coefficients.

a_{0}x^{n}+a_{1}x^{2}+....a_{1}x+a_{0}

For example:

3) Every time a polynomial equation, like a quadratic equation which is an univariate polynomial one, has its discriminant following this rule:

\Delta < 0\\b^{2}-4*a*c

We'll have <em>n </em>different complex roots, not necessarily 2i.

For example:

Taking 3 polynomial equations with real coefficients, with

\Delta < 0

-4x^2-x-2=0 \Rightarrow S=\left \{ x'=-\frac{1}{8}-i\frac{\sqrt{31}}{8},\:x''=-\frac{1}{8}+i\frac{\sqrt{31}}{8} \right \}\\-x^2-x-8=0 \Rightarrow S=\left\{\quad x'=-\frac{1}{2}-i\frac{\sqrt{31}}{2},\:x''=-\frac{1}{2}+i\frac{\sqrt{31}}{2} \right \}\\x^2-x+30=0\Rightarrow S=\left \{ x'=\frac{1}{2}+i\frac{\sqrt{119}}{2},\:x''=\frac{1}{2}-i\frac{\sqrt{119}}{2} \right \}\\(...)

2.2) For other Polynomial equations with real coefficients we can see other complex roots ≠ 2i. In this one we have also -2i

x^5\:-\:x^4\:+\:x^3\:-\:x^2\:-\:12x\:+\:12=0 \Rightarrow S=\left \{ x_{1}=1,\:x_{2}=-\sqrt{3},\:x_{3}=\sqrt{3},\:x_{4}=2i,\:x_{5}=-2i \right \}\\

4 0
3 years ago
Maria and farida has 250 beads altogether. After Maria used 18 beads to make a bracket and farida gave away 2/5 of her beads, th
Elenna [48]

Answer:

Maria had 105 beads at first.

Step-by-step explanation:

Let number of beads Maria have be x.

Let number of beads Farida have be y.

Given:

Maria and Farida has 250 beads altogether.

Hence equation is represented as;

x+y =250 \ \ \ \ equation \ 1

Also Given:

Maria used 18 beads to make a bracket.

hence bead left with maria = x-18

farida gave away 2/5 of her beads.

Hence beads left with Farida = y - \frac{2}{5}y= \frac{5y}{5}-\frac{2y}{5}=\frac{5y-2y}{5}=\frac{3y}{5}

Also they have the same number of beads left.

bead left with maria = beads left with Farida

x-18= \frac{3y}{5}\\5(x-18)=3y\\5x-90=3y\\5x-3y =90 \ \ \ \ equation \ 2

Now Multiplying equation 1 with 3 we get;

3(x+y)=3\times250 = 3x+3y = 750 \ \ \ \ equation \ 3

Now adding equation 2 by equation 3 we get;

(5x-3y)+(3x+3y) = 750+90\\5x-3y+3x+3y = 840\\8x=840\\x=\frac{840}{8}=105

we know the value of x = 105

hence substituting value of x in equation 1 we get;

105+y=250\\y=250-105 =145

Maria had 105 beads and Farida had 145 beads at first.

Final Answer: Maria had 105 beads at first.

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What is the range of function g? g(x) = sqrt(x - 1) + 2
BabaBlast [244]

Answer:

Answer OA. y >2

Step-by-step explanation:

I took the quiz on k12

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