Answer:
= 30 km
Step-by-step explanation:
12.5 * 240/100
<em><u>= 30 km</u></em>
The information given requires you to rework the formula as :
distance÷time=rate
so then plug in values to get
5÷2=rate
and the answer will be 2.5 as your rate
We know:
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and

These expressions have an
term in common. We can combine them if we can find forms of the expressions in terms of
:


Now, because
(by the reflexive property), we can write:

This is our answer, A.
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
Answer:
jezz
Step-by-step explanation:
WHAT?!!!!!!!!!!