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Lemur [1.5K]
3 years ago
14

Does 21, 10, and 9 be the measures of the sides of a triangle

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

no

Step-by-step explanation:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

9+10 > 21

19 >21

This is not true so it cannot make a triangle

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Which of the following is a true statement?
n200080 [17]

Answer:

3

Step-by-step explanation:

It depends on the denominator

For 3 where comparing 16 to 24

Of course its going to be 16

Hope this helps!

6 0
3 years ago
Where can the perpendicular bisectors of the sides of a right triangle intersect?
vagabundo [1.1K]
The <span>perpendicular bisectors of the sides of a right triangle intersect on the triangle. The correct option among all the options that are given in the question is the first option or option "a". I hope that this is the answer that you were looking for and it has actually come to your help.</span>
5 0
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Read 2 more answers
You estimate that a jar contains 98 marbles. The actual number of marbles is 90. Find a percent of error.
pantera1 [17]

Answer:

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3 0
3 years ago
Match the equations representing parabolas with their directrixes. y + 8 = 3(x + 2)2 y − 14 = -(x − 3)2 y + 7.5 = 2(x + 2.5)2 y
Shkiper50 [21]

Answer:

Part 1) y+8=3(x+2)^{2} -----> y=-8.08

Part 2) y-14=-(x-3)^{2} ---->  y=14.25

Part 3) y+7.5=2(x+2.5)^{2} ---->  y=-7.625

Part 4) y-17=-(x-3)^{2} -----> y=17.25

Part 5) y+7=(x-4)^{2} ----> y=-7.25

Part 6) y-6=-(x-1)^{2} ---->  y=6.25

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

y-k=\frac{1}{4p}(x-h)^{2}

where

(h,k) is the vertex

The directrix is

y=k-p

case 1) we have

y+8=3(x+2)^{2}

the vertex is the point (-2,-8)  

\frac{1}{4p}=3

p=\frac{1}{12}

The directrix is equal to

y=-8-\frac{1}{12}=-8.08

case 2) we have

y-14=-(x-3)^{2}

the vertex is the point (3,14)  

\frac{1}{4p}=-1

p=-\frac{1}{4}

The directrix is equal to

y=14+\frac{1}{4}=14.25

case 3) we have

y+7.5=2(x+2.5)^{2}

the vertex is the point (-2.5,-7.5)    

\frac{1}{4p}=2

p=\frac{1}{8}    

The directrix is equal to

y=-7.5-\frac{1}{8}=-7.625

case 4) we have

y-17=-(x-3)^{2}

the vertex is the point (3,17)      

\frac{1}{4p}=-1

p=-\frac{1}{4}    

The directrix is equal to

y=17+\frac{1}{4}=17.25

case 5) we have

y+7=(x-4)^{2}

the vertex is the point (4,-7)      

\frac{1}{4p}=1

p=\frac{1}{4}    

The directrix is equal to

y=-7-\frac{1}{4}=-7.25

case 6) we have

y-6=-(x-1)^{2}

the vertex is the point (1,6)      

\frac{1}{4p}=-1

p=-\frac{1}{4}    

The directrix is equal to

y=6+\frac{1}{4}=6.25

5 0
3 years ago
PLEASE HELP ME !!!!!
Nuetrik [128]
I would say A. I hope I am right. I dunno if it would be A. or C.  But I think A would be the better pick.
4 0
3 years ago
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