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3 years ago

A function, h(x), is defined as shown.

Mathematics

1 answer:

joja [24]3 years ago

8 0

Answer:

Graph B

Step-by-step explanation:

Just took test

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PLEASEEEE HELPPPPPP ASAPPPPP

Burka [1]

Answer:

7.07

Step-by-step explanation:

Angle M is 63 degrees because all 3 angles must add to 180.

Now use the law of sines:

sin(90)/x = sin(63)/6.3

Cross multiply: 6.3 sin (90) = x sin (63)

Divide by sides by sin (63): (6.3 sin (90))/sin (63) = x

Use a calculator: 7.07

5 0

3 years ago

I giveeeeeeeeeeeeee brainlilst

Keith_Richards [23]

Answer:

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3 0

3 years ago

Original price: 340.00 <br>percent of mark - up: 5%

koban [17]

Answer:34.0

Step-by-step explanation:

6 0

3 years ago

An economist wants to estimate the mean income for the first year of work for college graduates who have had the profound wisdom

suter [353]

Answer:

We need at least 601 incomes.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How many such incomes must be found if we want to be 95% confident that the sample mean is within $500 of the true population mean?

We have to find n, for which $M = 500, \sigma = 6250$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$500 = 1.96*\frac{6250}{\sqrt{n}}$

$500\sqrt{n} = 1.96*6250$

$\sqrt{n} = \frac{1.96*6250}{500}$

$(\sqrt{n})^{2} = (\frac{1.96*6250}{500})^{2}$

$n = 600.25$

Rounding up

We need at least 601 incomes.

3 0

4 years ago

Is "70 Thousand" standard or written form? Or both?

Andre45 [30]

I think 70 thousand is Both

6 0

3 years ago

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