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Juliette [100K]
3 years ago
6

Which of the following is true?

Computers and Technology
1 answer:
Softa [21]3 years ago
4 0
C or d i would think 
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"HotelExp” is a 3-D range name applied to the workbook shown.
Ganezh [65]

Answer:

all cells in the B column of any worksheet in this workbook

Explanation:

It seems each worksheet covers total expenses for each month, and hence workbook must have 12 such with one month for each worksheet. Also, the 3D range is a special option in Excel to reference all cells or a selected group of cells for all the worksheets. However, it should be all B cells as B2: B4 apart from this, others in B column also has expenses. And hence, the above option is the correct one.

3 0
3 years ago
Which of the following is not a component of the programming phase of facility construction? deciding what to build examining sp
Anika [276]

Answer: designing the facility with architects.

Explanation: The programming phase of a facility construction has nothing to do with the architectural design of the facility. The programming phase usually involves ; Determining the needs of intended or impending users, estimated construction cost, required area for the project. The programming phase may involve individual or joint questioning or fact finding from the intended occupants or user group to determine their needs in terms of systems and infrastructure, security and so on. It also gets intended occupants informed on the features, use and design of the intended project. It also examines the effect of the project on structures previously existing in the environment.

4 0
3 years ago
(a) How many locations of memory can you address with 12-bit memory address? (b) How many bits are required to address a 2-Mega-
I am Lyosha [343]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit  memory  to add in 2 location:

\to \frac{0}{1}  =2^1  \ (\frac{m}{m}  \ location)

The address of 2-bit  memory to add in 4 location:

\to \frac{\frac{00}{01}}{\frac{10}{11}}  =2^2  \ (\frac{m}{m}  \ location)

similarly,

Complete 'n'-bit memory address' location number is = 2^n.Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

= 2^n \\\\ = 2^{12} \\\\ = 4096

In point b:

\to Let \  Mega= 10^6

              =10^3\times 10^3\\\\= 2^{10} \times 2^{10}

So,

\to 2 \ Mega =2 \times 2^{20}

                 = 2^1 \times 2^{20}\\\\= 2^{21}

The memory position for '2^n' could be 'n' m bits'  

It can use 2^{21} bits to address the memory location of 21.  

That is to say, the 2-mega-location memory needs '21' bits.  

Memory Length = 21 bit Address

In point c:

i^{th} element array addresses are given by:

\to address [i] = B+w \times (i-LB)

_{where}, \\\\B = \text {Base  address}\\w= \text{size of the element}\\L B = \text{lower array bound}

\to B=\$ 52\\\to w= 4 byte\\ \to L B= 0\\\to address  = 10

\to address  [10] = \$ 52 + 4 \times (10-0)\\

                       =   \$ 52   + 40 \ bytes\\

1 term is 4 bytes in 'MIPS,' that is:

= \$ 52  + 10 \ words\\\\ = \$ 512

In point d:

\to  base \ address = \$ t 5

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are  < 4 byte

Calculating address:

\to address  [5] = \$ t5 + 4 \times (5-0)\\

                     = \$ t5 + 4 \times 5\\ \\ = \$ t5 + 20 \\\\= \$ t5 + 20  \ bytes  \\\\= \$ t5 + 5 \ words  \\\\= \$ t 10  \ words  \\\\

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Answer:

a standard size Shani thing try Tuscon design retain watching we ftrtttttt5yu haha driving

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Shannon has been a member of her schools newspaper club for two years and takes writing workshops during her free time. What car
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Journalism definitely -------------
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