Remember that the formula for the perimeter of a rectangle is:
- is the width of the rectangle
- is the length of the rectangle
Thus, in this case, you can see that we are adding two of the same monomials and two of another monomial. One monomial is and another monomial is . In this case, these monomials would fulfill the perimeter equation of a rectangle.
Applying this perimeter structure, we can find that this expression represents a perimeter equation of a rectangle with sides x + 15 and x + 5.
Smaller Number is S
Larger Number is S + 13
Smaller # + Larger # = 61
S + S + 13 = 61
2S + 13 = 61
2S = 61 - 13
2S = 48
S = 48/2
S = 24
Larger # = S + 13
Larger # = 24 + 13
Larger # = 37
Check. .. 24 + 37 = 61. CORRECT!
Smaller Number is 24
Larger Number is 37
3yz²-4y²z+6y³-2z³
First group the terms with the coefficients 3 and 6 and 4 and 2 together.
3yz²+6y³-4y²z-2z³
And then factor the GCF from the first two terms and the last two.
3y(z²+2y²)-2z(2y²+z²) The two binomials match so we can group 3y and -2z
(3y-2z)(z²+2y²)
answer: C
100/2 = 50 pies per hour
350/50 = 7 hours