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choli [55]
4 years ago
14

21. Mahina measured the diameter of a circle to be 6.5 inches. What is the circumference of that circle to the

Mathematics
1 answer:
nlexa [21]4 years ago
6 0

Answer:

20 inch

Step-by-step explanation:

Diameter, D = 6.5in

Circumference

= π x D

= 3.142 x 6.5

= 20.42

= 20 in (rounded to nearest in)

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The area of a parallelogram is 12 ftsquared and the height is 4 ft. Find the length of the corresponding base.
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The length is 3 ft 4 times 3 =12
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3 years ago
There are (43)2⋅ 40 strawberries on a farm. What is the total number of strawberries on the farm?
Kazeer [188]

Answer:

3,440 strawberries

Step-by-step explanation:

Because of PEMDAS you want to start with the parentheses, and want to treat them like the distributive property.

So,

43 x 2 = 86

Then,

86 x 40 = 3440.

I hope that helps!!

6 0
3 years ago
What is 10 to the power of 3 multiply by 17.55?
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3 years ago
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Represent the following expressions with disks, regrouping as necessary. To the right record the partial products vertically 4*2
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2 27                     The 2 is showing that you carry that over when multiplying                                              the 4 and 2
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7 0
4 years ago
Read 2 more answers
!!PLEASE HELP ME ANSWER!!
Igoryamba

Answer:

x = \sqrt{w(w+z)}

Step-by-step explanation:

By the Pythagorean theorem, triangle BCD has

y^2 = x^2 - w^2

and triangle ABD has

v^2 = y^2 + z^2.

Substituting the first equation into the second equation for y^2 gives the equation

v^2 = (x^2 - w^2) + z^2

Now triangle ABC has

(w+z)^2 = x^2 + v^2

Expanding out the left side, w^2 + 2wz + z^2 = x^2 + v^2.

Now substitute the equation from before, v^2 = x^2 - w^2 + z^2, into the new equation.

w^2 + 2wz + z^2 = x^2 + (x^2 - w^2 + z^2)

w^2 + 2wz + z^2 =2x^2 - w^2 + z^2

We work to isolate x^2 by adding w^2 to both sides of equation and subtracting z^2 from both sides.

2w^2 + 2wz = 2x^2

Divide both sides by 2 and you get w^2 + wz = x^2

Assume that x is positive and square root both sides to get the final result of

x = \sqrt{w^2 + wz} = \sqrt{w(w+z)}

4 0
3 years ago
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