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2 years ago

The general formula of a parabola with a vertical axis is derived using the focus point and the __________ formula.

Mathematics

1 answer:

Y_Kistochka [10]2 years ago

8 0

This would be the Distance formula

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Radius is 21 5/8 incercepted by 5Pi/6? What is arc lenght?

vesna_86 [32]

9514 1404 393

Answer:

(18 1/48)π ≈ 56.61 units

Step-by-step explanation:

Arc length is the product of radius and intercepted arc in radians:

s = rθ

s = (21 5/8)(5π/6) = (18 1/48)π ≈ 56.61 . . . units

7 0

3 years ago

WILL GIVE BRAINILEST TO CORRECT ANSWER! TYSM IF U ANSWER :D

Jet001 [13]

Answer:

2/3 is bigger than 5/8 because 5/8 is split into smaller portions

Step-by-step explanation:

hope this helps

8 0

2 years ago

Below are five number sequences.

oksian1 [2.3K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

2 years ago

9. How many gallons of paint will you need to buy if you are painting a room that is 30 ft by

pentagon [3]

Answer:

To paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon

Step-by-step explanation:

Given as :

The Length of wall = L = 50 ft

The width of wall = W = 30 ft

The height of wall = H = 50 ft

Each gallon of paints should cover 300 sq feet

Let the amount o gallon required to paint the room = x

SO, Area of four wall = 2 × ( L + W ) × H

Or, Area of four wall = 2 × ( 50 + 30 ) × 50

Or, Area of four wall = 2 × ( 80 ) × 50

SO, Area of four wall = 8000 ft²

∵ To paint 300 sq ft the amount of paint required = 1 gallon

∴ To paint 8000 sq ft the amount of paint required = 26.67 gallon

Hence ,to paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon answer

6 0

3 years ago