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8_murik_8 [283]

3 years ago

8

Write, sixty-one billion, four hundred- forty -two million, six hundred sixty-nine thousand, thirty four. Write that in standard

form

1 answer:

docker41 [41]3 years ago

5 0

Answer:

61,442,669,034

Step-by-step explanation:

Standard form will always be in number form.

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The random variable K has a geometric distribution with mean 16. Which of the following is closest to the standard deviation of

sdas [7]

Answer: d. 15.49

Step-by-step explanation:

Given : The random variable K has a geometric distribution with mean 16.

Formula for Mean and standard deviation in geometric distribution:

$\mu=\dfrac{1}{p}$ (1)

$\sigma=\dfrac{\sqrt{1-p}}{p}$ (2), where p is the probability of success in each trial.

Since $\mu=16$ (Given)

Then from (1) ,

$\dfrac{1}{p}=16\\\Rightarrow\ p=\dfrac{1}{16}=0.0625$

Put value of p in (2),

$\sigma=\dfrac{\sqrt{1-0.0625}}{0.0625}=\dfrac{\sqrt{0.9375}}{0.0625}$

$=\dfrac{0.968245836552}{0.0625}$

$=15.4919333848\approx15.49$

Hence, the standard deviation of random variable K is closest to 15.49.

Therefore , the correct answer is d. 15.49 .

6 0

3 years ago

What is love<br>rsx-ubiq-gna

noname [10]

Answer:

Love encompasses a range of strong and positive emotional and mental states, from the most sublime virtue or good habit, the deepest interpersonal affection, to the simplest pleasure.

OR

love is a strong and lasting affection between spouses or lovers who are in a happy, passionate and fulfilling relationship.

Love means to be deeply committed and connected to someone or something.

7 0

3 years ago

Each of the 6 cats in a pet store was weighed. Here are their weights (in pounds):

pantera1 [17]

Mean: add up all numbers and divide by the number of data
12 + 12 + 7 + 5 + 10 + 16 = 62
62/6 = 10.333... (mean)
5,7,10,12,12,16
Find what’s in the middle
The medium is 11

7 0

3 years ago

Please this is due tonight!!! Express given logarithm in terms of a, b and c.

KATRIN_1 [288]

$\textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_5(18)\implies \cfrac{\log(18)}{\log(5)}\implies \cfrac{\log(2\cdot 3\cdot 3)}{\log(5)}\implies \cfrac{\log(2)+\log(3)+\log(3)}{\log(5)}$

$\begin{cases} \log(3)=a\\ \log(2)=b\\ \log(5)=c \end{cases}\implies \cfrac{b+a+a}{c}\implies \cfrac{b+2a}{c} \\\\[-0.35em] ~\dotfill\\\\ \log_5^2(18)\implies [\log_5(18)]^2\implies \left( \cfrac{b+2a}{c} \right)^2\implies \cfrac{(b+2a)^2}{c^2} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{b^2+4ab+4a^2}{c^2}~\hfill$

8 0

3 years ago

Which methods can you use to solve this problem: <br> X^2 -47=0

ivann1987 [24]

This is the awnser too this one

5 0

3 years ago