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8_murik_8 [283]

3 years ago

8

Write, sixty-one billion, four hundred- forty -two million, six hundred sixty-nine thousand, thirty four. Write that in standard

form

1 answer:

docker41 [41]3 years ago

5 0

Answer:

61,442,669,034

Step-by-step explanation:

Standard form will always be in number form.

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pav-90 [236]

Answer:

37.62 degrees + 47.87 degrees = 85.49 degrees

Step-by-step explanation:

For this question we are trying to find the "absolute value" between these 2 numbers, because one of the numbers are negative and the other one is positive, we are going to add both of them together. That is how we got 85.49. In a different equation, we might have done something different.

8 0

3 years ago

Dibujar el rombo que pasa por los puntos ( 1,4 ) ( 3,1 ) ( 5,4 ) (3,7) rapido es para una tarea

tresset_1 [31]

Answer:

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Step-by-step explanation:

3 0

4 years ago

N(n+1)+2n+1<br> expand and simplicity

meriva

Answer:

n² + 3n +1

Step-by-step explanation:

n(n+1) + 2n + 1

<h3>i) distribute n into the parantheses</h3>

= (n×n) + (n×1) + 2n + 1

= n² + n + 2n + 1

<h3>ii) collect like terms</h3>

= n² + 3n +1

6 0

3 years ago

7 to the 3rd power multiplied by 16 to the negative 9th power. Rewrite the expression using only positive exponents.

jekas [21]

Answer:

7^3×1/(16)^9...........

5 0

4 years ago

On a December day, the probability of snow is 0.30. The probability of a "cold" day is 0.50. The probability of snow and "cold"

Margarita [4]

Answer:

Yes, snow and cold weather are independent.

Step-by-step explanation:

We are given the following in the question:

C: Cold weather

S: Snow

P(C) = 0.50

P(S) =0.30

$P(S\cap C) = 0.15$

We have to check whether snow and cold whether are independent events.

If the events A and B are independent then,

$p(A\cap B) = P(A)\times P(B)$

Checking,

$p(S\cap C) = P(S)\times P(C)\\0.15 = 0.30\times 0.50$

Thus, the two events are independent.

For mutually exclusive events

$P(A\cap B) = 0$

Thus, the given events are not mutually exclusive.

8 0

3 years ago