All categories

2 years ago

How many stamps will each have?!!

Mathematics

1 answer:

Leto [7]2 years ago

3 0

Hey mate!
You stuck?

Xian and Kai would both need to receive stamps for 6 months to eventually have the same amount of stamps.

Xian: 12 stamps from club x 6 months + 56 stamps = 128
Kai: 8 stamps from club x 6 months + 80 stamps = 128

Hope this helps! :)

You might be interested in

PLEASE HELP FAST

skad [1K]

Answer:

The unit vector u is (-5/√29) i - (2/√29) j

Step-by-step explanation:

* Lets revise the meaning of unit vector

- The unit vector is the vector ÷ the magnitude of the vector

- If the vector w = xi + yj

- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w

- The unit vector u in the direction of w is u = w/IwI

- The unit vector u = (xi + yj)/√(x² + y²)

- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j

* Now lets solve the problem

∵ v = -5i - 2j

∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29

- The unit vector u = v/IvI

∴ u = (-5i - 2j)/√29 ⇒ spilt the terms

∴ u = (-5/√29) i - (2/√29) j

* The unit vector u is (-5/√29) i - (2/√29) j

8 0

2 years ago

What is fifty two thousand, fifty two in standard form

solniwko [45]

Fifty two thousand fifty two is equal to 52,052.

6 0

3 years ago

Read 2 more answers

John is making baked goods for a party. He can either make muffins or bread, and he can use blueberries, bananas, apples, or cho

Margarita [4]

The total number of possible choices that John had for making baked goods for the party is 8.

<h3>What is Combination?</h3>

The combination helps us to know the number of ways an object can be arranged without a particular manner. A combination is denoted by 'C'.

$^nC_r = \dfrac{n!}{r!(n-r)!}$

where,

n is the number of choices available,

r is the choices to be made.

We know that the number of choices with John for his baked goods is only two which are muffins or bread, therefore, the choices of the baked good can be written as $^2C_1$ .

Also, the number of choices with John for flavors is four which are blueberries, bananas, apples, or chocolate chips, therefore, the choices of the flavor can be written as $^4C_1$ .

Now, the total possible choices that John had

= The choices of the baked good x The choices of the flavor

$=\ ^2C_1 \times ^4C_1\\\\=\ 8$

Hence, the total number of possible choices that John had for making baked goods for the party is 8.

Learn more about Combination:

brainly.com/question/11732255

8 0

2 years ago

Answer ASAP

Talja [164]

Answer:

13 and 27

Step-by-step explanation:

y= x+14

x+y=40

x+ x+14=40

2x+14=40

40-14=26

so, 2x=26

26/2

=13

so, x=13 and

and y equal 40-13

y=27

3 0

1 year ago

Solve for x<br> 4(x + 1) = –28

lora16 [44]

Answer:

X=-8

Step-by-step explanation:

4x+4=-32

Add -4 to both sides

4x=-32

decide both sides by 4

x=-8

4 0

2 years ago