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3 years ago

2 4 8 16 what is the rule and the sixth number in the sequence answers

Mathematics

1 answer:

aleksklad [387]3 years ago

7 0

The sequence is incrementing by
${2}^{n}$
Therefore, the sixth number is
${2}^{6}$
Which is 64.

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The MoviePlex theater sold 1,456 tickets. The theater sold 6 times as many regular price tickets as it sold discount tickets. Ma

Lady bird [3.3K]

Jonah is the one that is correct because 1/6th of 1248 is 208. Then you add 1248 and 208 which is 1456 which is the correct answers

5 0

3 years ago

The sum of 3 times the value of x and 2 is equal to four less than five times the value of x. Which equation can be used to find

bonufazy [111]

The question has omitted options but i will solve, so you will just check my answer from the options you have.

Answer: The equation to find the value of x = 3x+ 2= 5x-4

The value of x= 3

Step-by-step explanation:

Step 1

The sum of 3 times the value of x and 2 is equal to four less than five times the value of x can be expressed as

3x+ 2= 5x-4

Step 2

Solving this equation to find the value of x , we have that

3x+ 2= 5x-4

3x-5x= -4-2

-2x= -6

x= -6/-2

x=3

5 0

3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$