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Ipatiy [6.2K]
3 years ago
12

In the diagram of the park, ADF~ BCF. The crosswalk at point A is about 20 yd long. A bridge across the pond will be built, from

point B to point C. What will the length of the bridge be?
Mathematics
1 answer:
velikii [3]3 years ago
6 0
<span>Since the 2 triangles are similar, their sides are proportional.
You also know AD is 20 yards, since it tells you that is the crosswalk length at A.
So the proportion is :
50 / 120 = 20 / BC
Or
if you flip it over,
120 / 50 = BC / 20
 Then you can solve for BC.
120 / 50 = BC / 20
(20)(120/50) = BC
BC = 48</span>
You might be interested in
Juan has x apples and 8 oranges. How many fruits does he have? Give your answer in terms of x
zubka84 [21]
X apples and 8 oranges = x+8

The answer is x+8.

Hope this helped☺☺
3 0
3 years ago
Can someone help me with these problems? I'm in k12 and this assignment was in classkick, so if anyone already completed this an
kherson [118]

<em>                       </em><u><em>SOLVING QUESTIONS FROM 1ST PAGE</em></u>

  • Given the point B(-5, 0)

y = -3x - 5

Putting x = -5, and y = 0 in y = -3x - 5

0 = -3(-5) - 5

0 = 15 - 5

0 = 10         ∵Putting B(-5, 0) in y = -3x - 5 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no        ∵ L.H.S ≠ R.H.S

  • Given the point C<em>(-2, 1)</em>

y = -3x - 5

Putting x = -2, and y = 1 in y = -3x - 5

1 = -3(-2) - 5

1 =  6 - 5

1 = 1         ∵Putting C(-2, 1) in y = -3x - 5 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes      ∵ L.H.S = R.H.S

  • Given the point D<em>(-1, -2)</em>

y = -3x - 5

Putting x = -1, and y = -2 in y = -3x - 5

-2 = -3(-1) - 5

-2 =  3 - 5

-2 = -2       ∵Putting D(-1, -2) in y = -3x - 5 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes       ∵ L.H.S = R.H.S

<em>                          </em><u><em>SOLVING QUESTIONS FROM 2ND PAGE</em></u>

  • Given the point B(6, 18)

y = -2x + 18

Putting x = 6, and y = 18 in y = -2x + 18

18 = -2(6) + 18

18 = -12 + 18

18 = 6         ∵Putting B(6, 18) in y = -2x + 18 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no       ∵ L.H.S ≠ R.H.S

  • Given the point C(9, 24)

y = 2x + 6

Putting x = 9, and y = 24 in y = 2x + 6

24 = 2(9) + 6

24 = 18 + 6

24 = 24      ∵Putting C(9, 24) in y = 2x + 6 rightly equates the equation.

As L.H.S = R.H.S

So,

Does this check?

Answer: yes       ∵ L.H.S = R.H.S

<em>               </em><u><em>SOLVING QUESTIONS FROM 3RD PAGE</em></u>

  • Given the point D(2, 7)

y = 3x + 4

Putting x = 2, and y = 7 in y = 3x + 4

7 = 3(2) + 4

7 = 6 + 4

7 = 10         ∵Putting D(2, 7) in y = 3x + 4 does not equate the equation.

As L.H.S ≠ R.H.S

So,

Does this check?

Answer: no       ∵ L.H.S ≠ R.H.S

<em>                       </em><u><em>SOLVING QUESTIONS FROM 4th PAGE</em></u>

<em>b. Which function could have produced the values in the table.</em>

<em>A. y = 3x + 4                            </em>

<em>B. y = -2x + 18</em>

<em>C. y = 2x + 6</em>

<em>D. y = x + 9</em>

<em>The Table:</em>

<em>x             y</em>

3            12

6            18

9            24

<em>Checking A) y = 3x + 4</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = 3x + 4</em>

For (3, 12)

y = 3x + 4

12 = 3(3) + 4

<em>12 = 13   </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no       ∵ L.H.S ≠ R.H.S

For (6, 18)

18 = 3(6) + 4

18 = 18 + 4

<em>18 = 22   </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no       ∵ L.H.S ≠ R.H.S

For (9, 24)

24 = 3(9) + 4

24 = 27 + 4

<em>24 = 31   </em>∵ L.H.S ≠ R.H.S

Does this check?

Answer: no       ∵ L.H.S ≠ R.H.S

So, the equation y = 3x + 4 could have not produced the all values in the table as the the ordered pairs in table do not satisfy(equate) the equation.

<em>Checking B) y = -2x + 18</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = -2x + 18</em>

  • <em>For (3, 12) </em>⇒ y = -2x + 18 ⇒ 12 = -2(3) + 18 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
  • <em>For (6, 18)</em> ⇒ y = -2x + 18 ⇒ 18 = -2(6) + 18 ⇒ 18 = 6 ⇒ <em>L.H.S ≠ R.HS</em>
  • <em>For (9, 24)</em> ⇒ y = -2x + 18 ⇒ 24 = -2(9) + 18 ⇒ 18 = 0 ⇒ <em>L.H.S ≠ R.HS</em>

So, y = -2x + 18 could have not produced all the values in the table, as (6, 18) does not equate the equation.

<em>Checking C) y = 2x + 6</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = 2x + 6</em>

  • <em>For (3, 12) </em>⇒ y = 2x + 6 ⇒ 12 = 2(3) + 6 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
  • <em>For (6, 18) </em>⇒ y = 2x + 6 ⇒ 18 = 2(6) + 6 ⇒ 18 = 18 ⇒<em> L.H.S = R.HS</em>
  • <em>For (9, 24) </em>⇒ y = 2x + 6 ⇒ 24 = 2(9) + 6 ⇒ 24 = 24 ⇒<em> L.H.S = R.HS</em>

So, y = 2x + 6 could have produced the values of in the table as all the orders pairs in the table satisfy/equate the equation.

<em>Checking D) y = x + 9</em>

<em>Putting (3, 12), (6, 18) and (9, 24) in y = x + 9</em>

  • <em>For (3, 12) </em>⇒ y = x + 9 ⇒ 12 = 3 + 9 ⇒ 12 = 12 ⇒<em> L.H.S = R.HS</em>
  • <em>For (6, 18) </em>⇒ y = x + 9 ⇒ 18 = 6 + 9 ⇒ 18 = 15 ⇒ <em>L.H.S ≠ R.HS</em>
  • <em>For (9, 24) </em>⇒ y = x + 9 ⇒ 24 = 9 + 9 ⇒ 24 = 18 ⇒<em> L.H.S ≠ R.HS</em>

So, y = x + 9 could have also not produced all the values in the table, as (6, 18) and (9, 24) do not satisfy/equate the equation.

So, from all the verification we conclude that:

<u>HENCE, ONLY </u><u>y = 2x + 6</u><u> COULD HAVE PRODUCED THE VALUES IN THE TABLE AS ALL THE ORDERED PAIRS OF THE TABLE SATISFY/EQUATE THE EQUATION.</u>

<em>                  </em><u><em>SOLVING QUESTIONS FROM 5th PAGE</em></u>

<em>What is the domain and range of the relation?</em>

{(-3, 7), (6, 2), (5, 1), (-9, -6)}

  • Domain: Domain is the set of all the x-coordinates of the ordered pairs of  the relation, meaning the all first elements of the ordered pairs in a relation include in the domain of the relation.
  • Range: Range is the set of all the y-coordinate of the ordered pairs of the relation, meaning the all second elements of the ordered pairs in a relation include in the range of the relation.

As the given relation is {(-3, 7), (6, 2), (5, 1), (-9, -6)}

The <em>domain</em> is: {-3, 6, 5, -9}

<em>Note: generally, we write the numbers in ascending order for both the domain and range.</em>

The domain could also be written in order as: {-9, -3, 5, 6}

The <em>range</em> is: {7, 2, 1, -6}

The range could also be written in order as: {-6, 1, 2, 7}

Keywords: equation, point, ordered pair, domain, range

Learn more about points and equation from brainly.com/question/12597810

<em>#learnwithBrainly</em>

8 0
3 years ago
1 – 4k – 5 = -5 +4- 7K + 6<br> K = 3<br> K= -5<br> K=0<br> K = -7
sveta [45]

Answer:

K=3

Step-by-step explanation:

1 - 4K = 4 - 7K + 6

1 - 4K = 10 - 7K

-4K + 7K = 10 - 1

3K = 9

3K/3 = 9/3

K = 3

4 0
3 years ago
Select the correct difference.
scZoUnD [109]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

5d^2+4d-3-(2d^2-3d+4)

We need to find the correct difference.

Collect the like terms together.

5d^2+4d-3-(2d^2-3d+4)\\\\=5d^2+4d-3-2d^2+3d-4\\\\=5d^2-2d^2+4d+3d-3-4\\\\=3d^2+7d-7

Hence, First option is correct.

5 0
3 years ago
Read 2 more answers
Find the probability of each event. Answer IN FRACTION form.
IgorLugansk [536]

Answer:

= 8/6435

Step-by-step explanation:

Number of black balls = 8

Number of Brown balls = 5

Total number of balls = 8+5 = 13

Pr (8 balls picked at random are black ) =

Number of black balls / Total number of balls.

1st Pr ( 8 balls picked are black) = 8/13

Pr (2nd random pick) = 7/12

Pr (3rd random pick) = 6/ 11

Pr (4th random pick) = 5/10

Pr (5th random pick) = 4/9

Pr (6th random pick) = 3/7

Pr (7th random pick) = 2/6

Pr (8th random pick) = 1/5

Pr (8 balls picked at random are black ) = 8/13 * 7/12 * 6/11 * 5/10 * 4/9 * 3/7 * 2/6 * 1/5

= 8/13 * 7/12 * 6/11 * 1/2 * 4/9 * 3/7 * 1/3 * 1/5

= 8/6435

But pls note, I solved it such that there wasn't a replacement after each pick.

Math is fun

4 0
3 years ago
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