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3 years ago

Pls help, I need to get my test done b4 the end of today, and I still need to finish the rest of the questions!

Mathematics

1 answer:

aalyn [17]3 years ago

5 0

The equation in required form is: $(x-4)^2 = 3$

Step-by-step explanation:

Given equation is:

$x^2-8x+13=0$

to write the equation in $(x-a)^2 = b$ form where a and b are integers

subtracting 13 from both sides

$x^2-8x+13-13=0-13\\x^2-8x = -13$

To complete the square:

2.x.b = 8x

b = 8x/2x = 4

So adding (4)^2 on both sides

$(x)^2-8x+(4)^2 = -13+(4)^2\\(x-4)^2 = -13+16\\(x-4)^2 = 3$

Hence,

The equation in required form is: $(x-4)^2 = 3$

Keywords: Quadratic equation, Vertex form

Learn more about quadratic equation at:

#LearnwithBrainly

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Solve for v: -v+1=1 + 8v

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Step-by-step explanation:

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Step 1: Simplify both sides of the equation.

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Divide the following polynomials (a4 + 4b4) ÷ (a2 - 2ab + 2b2)

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(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer

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(a - b)^2 = a^2 - 2ab + b^2 => square of deference
and of course one of most important ones:
a^2 - b^2 = (a - b)(a + b) => difference of squares
Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
a^4 + 4b^4 => i.e. 4a^2b^2 ,
a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)

Greetings!

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