Question

Media aritmetica a 3 nr este 24 . Al doilea numar e cu 50% mai mare decat primul iar al treilea este cu o treime mai mare decat al doilea. Care sunt numerele?​

Answer 1

Answer:

The numbers are 16,24 and 32

Step-by-step explanation:

The question in English is

The arithmetic mean of 3 numbers is 24. The second number is 50% greater than the first and the third is one third greater than the second. What are the numbers?

Let

x---> the first number

y ---> the second number

z ---> the third number

we know that

The arithmetic mean of 3 numbers is 24

so

$\frac{x+y+z}{3}=24$

$x+y+z=72$ ----> equation A

The second number is 50% higher than the first

Remember that

$100\%+50\%=150\%=150/100=1.50$

so

$y=1.5x$

$x=\frac{2}{3}y$ ----> equation B

The third number is is one third greater than the second

Remember that

$1+\frac{1}{3}=\frac{4}{3}$

so

$z=\frac{4}{3}y$ ----> equation C

substitute equation B and equation C in equation A

$\frac{2}{3}y+y+\frac{4}{3}y=72$

solve for y

$3y=72\\y=24$

Find the value of x

$x=\frac{2}{3}(24)=16$

Find the value of z

$z=\frac{4}{3}(24)=32$

therefore

The numbers are

16,24 and 32