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Lilit [14]
3 years ago
11

What is the area of a circle whose diameter is 22?

Mathematics
1 answer:
Rina8888 [55]2 years ago
7 0

diameter 22 equals radius of 11

Area = PI * radius^2 = PI * 11 * 11

Area = 380.1327110844



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PLEASE HELP ME IM GIVEING POINTS AWAY BEING TOO LAZY TOO SOLVE MY CLASS WORK LOL
katen-ka-za [31]

Answer:

17/24

Step-by-step explanation:

Apply the AB rule, Adjust the fractions based on LCM, then you want to apply the a/b fraction rule which would allow you to do -15+23/24 which gives you 17/24. Hope this helps!

3 0
3 years ago
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Jill is thinking of a number. Twenty less than one forth of the number is -45. Find Jill's number.
Bezzdna [24]

Answer:

The number is -100, Jill can think of something else, now.

Step-by-step explanation:

x = the number

x/4 - 20 = -45 {twenty less than one-fourth of the number is -45}

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5 0
2 years ago
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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.
oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

H_0: \mu=2.4\\\\H_a:\mu> 2.4

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58

The degrees of freedom for this sample size are:

df=n-1=45-1=44

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.5801)=0.0066

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0
3 years ago
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it would be d.)54 miles

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