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schepotkina [342]
3 years ago
14

Type in expanded form. Use parentheses to indicate multiplication. (3x)²

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
Hint:  \bf (abc)^z\implies a^zb^zc^z\impliedby \textit{apply the exponent to "all" factors}
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What is the answer to this solution. -7r−4≥ 4r+2
tia_tia [17]

Answer:

The solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

-7r-4\ge \:4r+2

Add 4 to both sides

-7r-4+4\ge \:4r+2+4

Simplify

-7r\ge \:4r+6

Subtract 4r from both sides

-7r-4r\ge \:4r+6-4r

Simplify

-11r\ge \:6

Multiply both sides by -1 (reverses the inequality)

\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)

Simplify

11r\le \:-6

Divide both sides by 11

\frac{11r}{11}\le \frac{-6}{11}

Simplify

r\le \:-\frac{6}{11}

Therefore, the solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

7 0
2 years ago
X^3 + 6x + 5 =??<br> Explain your answer..
vovikov84 [41]

x^3 + 6x + 5 =

is the answer to the question you asked

7 0
3 years ago
Help me on this algebraic problem and please show work. (10 points) Thanks! :)
jonny [76]
4 - 2(x + 3) = 5
4 - 2x - 6 = 5
-2x - 2 = 5
-2x = 5 + 2
-2x = 7
x = -7/2 or = -3 1/2
5 0
3 years ago
Read 2 more answers
(A REAL ANSWER PLS, NO GUESSING)
Gemiola [76]
The answer would be 3 ft. 
4 0
3 years ago
Read 2 more answers
PLS HELP ILL MARK YOU AS BRAINLIEST
Alenkasestr [34]

Answer:

a= 78

Step-by-step explanation:

To solve subtract:

180-102= 78

Hope this helps!

4 0
2 years ago
Read 2 more answers
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