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3 years ago

5 lb. 10 oz. − 3 lb. 1 oz. = lb. oz.

Mathematics

2 answers:

FromTheMoon [43]3 years ago

7 0

Answer: 2lb. 9oz.

Step-by-step explanation: 5lb. - 3lb. is 2lb.

10oz. - 1oz. is 9oz.

Darina [25.2K]3 years ago

3 0

Answer:

2 lbs 9 oz

Step-by-step explanation:

Lets line up the ounces and pounds and subtract

5 lb. 10 oz.

− 3 lb. 1 oz.

------------------------

2 lbs 9 oz

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The volume of a cylinder whose base,area is 500sq.cm and height is 14 cm is cu.cm

Allisa [31]

<h3> $\huge\bigstar\:$ $\Huge\tt\underline\blue{ANSWER}$ </h3><h3 /><h3 /><h3>The area is 7000.</h3>

$\huge\bigstar\:$ $\Huge\tt\underline\red{EXPLAINATION}$

The base of the cylinder = 5000 sq.cm

Height = 14cm

The volume of the cylinder = 5000× 14 = 7000

<h3>HOPE IT HELPS YOU :)</h3>

6 0

4 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

One out of every 15 students are tardy to first hour. The principal is concerned because there are 600 students in school. How m

Natalija [7]

Answer: 40

Step-by-step explanation: 600 divided by 15

5 0

3 years ago

8x + 11 + 3x + 11 + 39 = 180

kow [346]

Answer:

Step-by-step explanation:

collect terms

11x+61=180

move numbers to one side and x to other

11x=180-61

11x=119

x=119/11=10.8

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3 years ago

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adoni [48]

1 is scalene, 2 is equilateral, and 3 is isosceles.

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3 years ago

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