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Anon25 [30]
3 years ago
13

How are both the graphs related, name a few mathematical ways they are related

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Hey, one immediate way these graphs are related is that both graphs have the same parent function -- y = x^2. Another way they are related is that they both have minimums (which only occurs for parabolas that open upward).

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Tori examined the pattern of exponents in the table.
vichka [17]

Answer:

The answer is actually B, C, and E

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Suppose the temperature outside is dropping 3 degrees each hour how much will the temperature drop in 8 hours
vovikov84 [41]
It would drop by 24 degrees

3 x 8 = 24

For each hour another long way is simple just do

3 x 4 = 12 now just double it
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6 0
4 years ago
第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows
tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

P(A/B)=\frac{P(A)*P(B/A)}{P(B)}

let A be the  event that the student knows the answer .

B be  the  event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}

Probability that the answer is correct ,given that he knows the answer is

P(E/A)=1

Probability that the answer is correct ,given that he guesses it is

P(E/B)=\frac{1}{3}   [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}

Substituting the values we get

P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }

=\frac{6}{30}*\frac{30}{18}  \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}

Therefore ,  the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0
1 year ago
If your algorithm runs its critical section 1 + 2 + 3 + ... + (n-2) + (n-1) + n times, what is the asymptotic behavior of the al
Paraphin [41]
If 1 and 2 becomes multiplayed gave 3 and 3+3=4 (4-2)+(4-1)= 2+3=4 and 4 is n.
4 0
3 years ago
12 − 7 = 2(3 + 5) + 6 − 17
larisa [96]

It equals 5- hope this helps---

5 0
4 years ago
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