Question

A basket contains four apples three peaches and four pears . you randamoly eat three pieces of fruit . the first one you want is a apple second two you eat are peaches . findt is the probability. A. 4/165. B. 25/572. C.20/429. D. 1/55

Answer 1

P(apple first) = 4/11
P(peach second) = 3/10
P(peach third) = 2/9
$P(desired\ selection)=\frac{4}{11}\times\frac{3}{10}\times\frac{2}{9}=\frac{4}{165}$
Choice A is correct.