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Mama L [17]
3 years ago
7

A basket contains four apples three peaches and four pears . you randamoly eat three pieces of fruit . the first one you want is

a apple second two you eat are peaches . findt is the probability. A. 4/165. B. 25/572. C.20/429. D. 1/55
Mathematics
1 answer:
sasho [114]3 years ago
5 0
P(apple first) = 4/11
P(peach second) = 3/10
P(peach third) = 2/9
P(desired\ selection)=\frac{4}{11}\times\frac{3}{10}\times\frac{2}{9}=\frac{4}{165}
Choice A is correct.
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Helpppppppp meeeeeee
natta225 [31]

Answer:

y = 14

Step-by-step explanation:

∠BCF and ∠EFH are same side interior angles and are supplementary, hence

5x - 66 +2x + 50 = 180

7x - 16 = 180 ( add 16 to both sides )

7x = 196 ( divide both sides by 7 )

x = 28

∠BCF = 5x - 66 = (5 × 28) - 66 = 140 - 66 = 74

∠ACD = ∠BCF ( vertical angles ), hence

9y - 52 = 74 ( add 52 to both sides )

9y = 126 ( divide both sides by 9 )

y = 14

6 0
3 years ago
SOMEONE HELP ASAPP!!
Vlad [161]
The answer is A

You’re welcome.
4 0
3 years ago
A study was done to compare people's religion with how many days that they have said they have been calm in the past three days.
nadezda [96]

Answer:

The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

Step-by-step explanation:

Represent the provided data as follows:

Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:

P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}

The number of Protestants surveyed is, <em>n</em> (Protestants) = 99.

The number of Protestants who were calm for 2 days,

<em>n</em> (Protestants who were calm for 2 days) = 6

The required probability is:

P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}\\=\frac{6}{99}\\ =0.060606\\\approx0.061

Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

3 0
3 years ago
Which is a correct two-column proof? Given: r || s Prove: ∠b and ∠h are supplementary. Picture 1, Picture 2, Picture 3 or none o
aliina [53]

Answer: The second proof table is the the proper proof table.

We always start out with what we are given, which in this case is r || s saying that r is parallel to s. Also, we always end up with what we want to prove which is angles b and h are supplementary. So this is the last line of the proof.

So far, this eliminates the first proof table because in this table, the last line says "angle c and angle h are supplementary" which is not what we want to end up with. We want the last line to say "angle b and angle h are supplementary".

We can also eliminate the third proof table because of the statement "angle d and angle h are supplementary". They are only supplementary if they are both right angles. Also, the reasoning of "alternate interior angles" is false as they are corresponding angles.

The only thing left is the second proof table which is correctly argued from start to finish.

1. r || s ........................ given

2. angle b = angle c ................ vertical angles

3. c and e are supplementary angles ....... same side interior

4. angle e = angle h ................. vertical angles

5. b and h are supplementary ...... substitution

Note: in line 5, we start with line 3's statement. Then we replace 'c' with 'b', at the same we replace 'e' with 'h'.

8 0
3 years ago
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Simplify square root of 2 over cube root of 2.
Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

\sqrt[n]{x}  =  {x}^{ \frac{1}{n} }

So you can rewrite the given fraction as

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }  =  {2}^{ \frac{1}{2} -  \frac{1}{3}  }

Since

\frac{1}{2}  -  \frac{1}{3}  =  \frac{3}{6}  -  \frac{2}{6}  =  \frac{1}{6}

the answer is

{2}^{ \frac{1}{6} }  \: or \:  \sqrt[6]{2}

3 0
3 years ago
Read 2 more answers
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