Answer:
The frequency of recessive allele should be 0.30.
Explanation:
According to Hardy-Weinberg equilibrium, sum of both dominant allele frequency (p) and recessive allele frequency (q) should be equal to 1 (p+q = 1).
Brown hair = dominant (p)
white hair = recessive (q)
49% mice are brown hair
so dominant genotype frequency = 0.49
According to Hardy-Weinberg principle, square root of the genotype (homozygous) is equal to allele frequency.
√p =√0.49 = 0.70
The dominant allele frequency is 0.7
Now, by this value we can find the recessive allele frequency by
p + q = 1
1 - 0.7 = 0.3
So, the recessive allele (white hair mice) frequency is 0.30.
Symbiosis is the relationship between fungus and Brazilian ant makes in a parasitic.
<h3>What is symbiosis?</h3>
- They live together in more or less close association or close union of two dissimilar organisms.
- A symbiosis between the ant and the fungi is parasitism because one of the specie is benefited, from its ability to reproduce and enlarge itself.
- The Brazilian ants and their fungi form a true symbiosis, with both forms benefiting from the relationship.
- Most Cordyceps species are known as endoparasitoids, parasitic mainly on insects and other arthropods, and a little are parasitic on other fungi.
To learn more about symbiosis refer to:
brainly.com/question/3350498
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1.Diatomic
2.polar
3.covalent
4.nonpolar
5.ionic
The survival of the cell depends on chromosome integrity.
