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Galina-37 [17]
4 years ago
15

Can someone help me with these two please ​

Mathematics
2 answers:
Xelga [282]4 years ago
7 0
Number 6 is 3 :)


.....
zvonat [6]4 years ago
5 0

Answer:

1.) a= -49

2.) t= 3

Step-by-step explanation:

You might be interested in
Among all pairs of numbers with a sum of 215, find the pair whose product is maximum. Write your answers as fractions reduced to
valentina_108 [34]

Answer:

Step-by-step explanation:

This is calculus, but I don't get fractions in the end. To maximize or minimize any function, you need to find the derivative of it, set it equal to 0, then solve for the critical values.

Our given equation is

x + y = 215 and we want to maximize the product, xy. Therefore,

y = 215 - x so its product in terms of x is

x(215-x) which is

215x -x^2.  The derivative of this is

215 - 2x. Set it equal to 0 to maximize it.

215 - 2x = 0 so

-2x = -215 and

x = 107.5.

Sub this in to solve for y:

y + 107.5 = 215 and

y = 107.5

The product is 11556.25, not that you need it.

6 0
3 years ago
5. The area of a circle is 78.5 cm2. What is the diameter of the circle?
stellarik [79]
The answer would be 10.
d=2A
π=2·78.5
π≈9.99746
7 0
3 years ago
7 more than the quotient of a number n and 4 is 9
JulijaS [17]
7+n/4=9
Or
N/4+7=9
Or
9=n/4+7
5 0
4 years ago
No Calculator SAT Math Questions
AlexFokin [52]

Answer: love you

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
This is confusing. help plz
Veseljchak [2.6K]
a=-1, because the parabola has the maximum, not the minimum, (∩)

The Vertex form of a parabola equation:
V(-3;4), so:
f(x)=a(x-p)^2+q
f(x)=-1(x+3)^2+4

*   f(x)=-(x+3)^2+4

The zeros and the conix form of a parabola equation:
x_1=-5
x_2=-1
f(x)=a(x-x_1)(x-x_2), so:

*   f(x)=-(x+5)(x+1)

We can also use the general form of a parabola:
f(x)=ax^2+bx+c 

f(x)=-(x+5)(x+1)=-(x^2+x+5x+5)=-x^2-x-5x-5=-x^2-6x-5

*   f(x)=-x^2-6x-5

The answers: A, C, E

:)
8 0
4 years ago
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