Answer:
a) 25.15
b)
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c) (x,y) = (1, -2pi)
Step-by-step explanation:
a)
First lets calculate the velocity, that is, the derivative of c(t) with respect to t:
v(t) = (-sin(t), cos(t), 2t)
The velocity at t0=4pi is:
v(4pi) = (0, 1, 8pi)
And the speed will be:
s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15
b)
The tangent line to c(t) at t0 = 4pi has the parametric form:
(x,y,z) = c(4pi) + t*v(4pi)
Since
c(4pi) = (1, 0, (4pi)^2)
The tangent curve has the following components:
x = 1
y = t
z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)
c)
The intersection with the xy plane will occurr when z = 0
This happens at:
t1 = -2pi
Therefore, the intersection will occur at:
(x,y) = (1, -2pi)
<h3>
Answer: b = 17</h3>
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Explanation:
The line must go through the point (5,2) which means x = 5 and y = 2 pair up together.
We'll plug these x and y values into the equation and solve for b.
y = -3x+b
2 = -3(5)+b
2 = -15+b
2+15 = b
17 = b
b = 17
The equation y = -3x+b turns into y = -3x+17
Answer:
m = 300
Step-by-step explanation:
multiply both sides of the equation by 5
9x40= 360
9x30= 270 so the common factor is 9 I have no idea about the exponent stuff
Answer:
Step-by-step explanation:
hope this helps
brainliest appreciated
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