Simplify. 13 – 81 – (12 : 3 + 1)2
1 answer:
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Answer:
Step-by-step explanation:
I don't know if you are a calculus student, but since calculus is the easiest way to solve this, that's what I used. The position equation is
and the velocity function, the first derivative, is
From Physics, you should know that the velocity of an object is 0 at its highest point. That means that if we sub in a 0 for the velocity and solve for t, we find the time at which the object is at its highest point. That is:
and
By the Zero Product Property,
-12 definitely does not equal 0, so that means that
t - 2 = 0 and
t = 2 seconds.
So at 2 seconds, the object is at its highest point. Go back to the position function now and sub in a 2 for t to find the height of the object at 2 seconds.
so
s(2) = 38 meters
Answer:
1i) nth term = 12(-b/4)^(n-1)
ii) nth term = 3(-1/9)^(n-1)
2i) Sixth term= (-3b^5)/256
ii) Eight term = -1/1594323
Question:
The complete question as found on brainly (question-10746111):
Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.
i) 12,-3b,......sixth term
ii) 3,-1/3,..........;8th term?
Step-by-step explanation:
1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.
i) 12,-3b,......;sixth term
1st term = a= 12
r = common ratio = 2nd term /1st term
r = -3b/12 = -b/4
Then we would find the nth term
See attachment for details
ii) 3,-1/3,..........;8th term
1st term = a= 3
r = common ratio = 2nd term /1st term
r = (-⅓)/3 = (-⅓)(⅓) = -1/9
Then we would find the nth term
See attachment for details
2) we are to determine the sixth term in (i) and eight term in (ii)
See attachment for details
Sixth term= (-3b^5)/256
Eight term = -1/1594323
