Question

The table represents a linear equation.which equation shows how (-10,8) can be used to write the equation of this line is point-slope form?

Answer 1

Answer:

The answer is $y-8=-0.2*(x+10)$

Step-by-step explanation:

In order to determine the correct option, we have to know about point-slope form.

The point-slope form is the way that we can create linear functions from a point and a slope. The formula is:

$y-y_1=m*(x-x_1)$

Where:

$(x_1,y_1)$: Coordinates of the point.

m: Slope

Also we can get the slope from two points. The formula is:

$m=\frac{y_2-y_1}{x_2-x_1}$

$(x_1,y_1)$: Coordinates of the first point.

$(x_2,y_2)$: Coordinates of the second point.

So first we determine the slope:

$P_1=(x_1,y_1)=(-10,8)\\P_2=(x_2,y_2)=(-5,7)\\\\m=\frac{7-8}{-5-(-10)}\\m=\frac{-1}{5}=-0.2$

Finally, the correct option is:

$y-8=-0.2*(x+10)$

Answer 2

Answer:

$\large\boxed{y-8=-0.2(x+10)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the table we have the points (-10, 8) and (10, 4). Substitute:

$m=\dfrac{4-8}{10-(-10)}=\dfrac{-4}{20}=-\dfrac{1}{5}=-0.2$

The equation of a line:

$y-8=-0.2(x-(-10))\\\\y-8=-0.2(x+10)$