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2 years ago

What is the PERIMETER of triangle ABC ?

Mathematics

2 answers:

gizmo_the_mogwai [7]2 years ago

6 0

The length of AC is 8

The length of 1/2 of AC = 4 (set the "4" point as D)
DC = 4

DC = 4,DB = 3, CB = x

Use the pythagoream theorem.

4² + 3² = x²
16 + 9 = x²
25 = x²

root both sides to isolate the x
√25 = √x²
x = √25
x, or CB = 5

Add all the sides together. Remember, CB = 5, DC = 4, & DB = 3
5 + 4 + 3 = 12

12, or (A) is your answer

hope this helps

Galina-37 [17]2 years ago

5 0

Answer: The correct option is (D) 18 units.

Step-by-step explanation: We are given to find the perimeter of triangle ABC.

As shown in the attached figure below, triangle ABC is divided into two right-angled triangles ABD and ACD.

From the figure, we note that

AC = 8 units.

And the side lengths AB and BC are calculated using Pythagoras theorem of right-angled triangles as follows :

$AB=\sqrt{AD^2+BD^2}=\sqrt{3^2+4^2}=\sqrt{25}=5~\textup{units},\\\\BC=\sqrt{CD^2+BD^2}=\sqrt{3^2+4^2}=\sqrt{25}=5~\textup{units}.$

We know that the perimeter of a triangle is equal to the sum of the lengths of the three sides.

Therefore, the required PERIMETER of ΔABC is given by

$P=AB+BC+AC=5+5+8=18~\textup{units}.$

Thus, the perimeter of ΔABC is 18 units.

Option (D) is CORRECT.

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3 years ago

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Answer:

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Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

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5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

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From Point 4 and point 5 above , we see that

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3 years ago

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From the information given, we have that;

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