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stepladder [879]
3 years ago
11

Mr. Kaplan bought 11 tickets to the circus and spent $50. He bought child tickets for $4 each and bought adult tickets for $7 ea

ch. How many child and adult tickets did Mr. Kaplan buy?
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0
Adult - 2 tickets . child- 9 tickets.
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If p is inversely proportional to the square of q, and p is 25 when q is 3, determine p
ArbitrLikvidat [17]

Answer:

p = 9 when q = 5.

Step-by-step explanation:

p is inversely proportional to the square of q

This means that:

p = \frac{k}{q^2}

In which k is a constant multiplier.

p is 25 when q is 3

We use this to find k.

p = \frac{k}{q^2}

25 = \frac{k}{3^2}

k = 25*9 = 225

So

p = \frac{225}{q^2}

Determine p when q is equal to 5.

p = \frac{225}{q^2} = \frac{225}{5^2} = 9

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6 0
2 years ago
Perimeter/area (triangles) ! PLZ HELP
BartSMP [9]

Answer:

50ft^2

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)
svlad2 [7]

Answer:

The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

Step-by-step explanation:

Given : Expression 7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

To Simplified : The expression

Solution :  

Step 1 - Write the expression

7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

Step 2- Simplify the roots and re-write as

16=2^3\times2 and 8=2^3

7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}

Step 3- Solve the multiplication

7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}

Step 4- Taking \sqrt[3]{2x} common from first two terms

\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}

\sqrt[3]{2x}-6\sqrt[3]{x}

Therefore, The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

5 0
3 years ago
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madreJ [45]
The answer is 66..................................................
5 0
3 years ago
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klasskru [66]
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Or, if you had drawn your graph with units of $100 dollars on the y-axis, then you might say that the slope was -1 / 1. 

The corresponding formula would of course be 

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slope = dy/dt = -100 

<span>as noted above.</span>
4 0
3 years ago
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