Y=(-1/6)x+5
m=(y2-y1)/(x2-x1)
m=(3-6)/(12-(-6))
m=(-3)/(18)
m=-1/6
y=mx+b
y=(-1/6)x+b
6=(-1/6)(-6)+b
6=1+b
b=5
y=(-1/6)x+5
1) Proportion a.
7 : 28 = 2 : 8
That means that the ratio 7 / 28 is equal to the ratio 2 : 8.
You can verify the equality by simplifying to the simplest form:
7 : 28 = 1 / 4 simplest form
2 : 8 = 1 / 4 simplest form, then the proportion is right.
In words that is 7 is to 28 as 1 is to 4 ← answer
2) Proportion b.<span>. 3⁄1 = 18⁄6
</span><span>
</span><span>
</span><span>In words: 3 is to q as 18 is to 6 ← answer
</span><span>
</span><span>
</span><span>You can verify the proportion by simplifiying the second fraction:
</span><span>
</span><span>
</span><span> 18 / 6 = [18 / 6] / [ 6 / 6] = 3 / 1
</span><span>
</span><span>
</span><span>3) Proportion c. 9 : 72 = 2 : 16
</span><span>
</span><span>
</span><span>In words: 9 is to 72 as 2 is to 16 ← answer
</span><span>
</span><span>
</span><span>Proove the proportion:
</span><span>
</span><span>
</span><span> 9 / 72 = 1 / 8
</span><span>
</span><span>
</span><span> 2 / 16 = 1 / 8
</span><span>
</span><span>
</span><span>4) Proportion d. 81⁄9 = 45⁄5</span>
In words: 81 is to 9 as 45 is to 5 ← answer
Proove it:
81 / 9 = 9
45 / 9 = 9
Answer:
4,5,27
Problem:
Boris chose three different numbers.
The sum of the three numbers is 36.
One of the numbers is a perfect cube.
The other two numbers are factors of 20.
Step-by-step explanation:
Let's pretend those numbers are:
.
We are given the sum is 36:
.
One of our numbers is a perfect cube.
where
is an integer.
The other two numbers are factors of 20.
and
where
.
![n^3+\frac{20}{k}+\frac{20}{i}=36](https://tex.z-dn.net/?f=n%5E3%2B%5Cfrac%7B20%7D%7Bk%7D%2B%5Cfrac%7B20%7D%7Bi%7D%3D36)
From here I would just try to find numbers that satisfy the conditions using trial and error.
![3^3+\frac{20}{2}+\frac{20}{2}](https://tex.z-dn.net/?f=3%5E3%2B%5Cfrac%7B20%7D%7B2%7D%2B%5Cfrac%7B20%7D%7B2%7D)
![27+10+10](https://tex.z-dn.net/?f=27%2B10%2B10)
![47](https://tex.z-dn.net/?f=47)
![3^3+\frac{20}{4}+\frac{20}{5}](https://tex.z-dn.net/?f=3%5E3%2B%5Cfrac%7B20%7D%7B4%7D%2B%5Cfrac%7B20%7D%7B5%7D)
![27+5+4](https://tex.z-dn.net/?f=27%2B5%2B4)
![36](https://tex.z-dn.net/?f=36)
So I have found a triple that works:
![27,5,4](https://tex.z-dn.net/?f=27%2C5%2C4)
The numbers in ascending order is:
![4,5,27](https://tex.z-dn.net/?f=4%2C5%2C27)
Given:
![\frac{475}{80}](https://tex.z-dn.net/?f=%5Cfrac%7B475%7D%7B80%7D)
Let's evaluate and find the quotient.
We have:
![\frac{475}{80}=5.9375](https://tex.z-dn.net/?f=%5Cfrac%7B475%7D%7B80%7D%3D5.9375)
SInce it is not a repeating decimal, we are asked to leave to answer as it is.
A repeating decimal is a decimal with digits or group of digits that repeats endlessly.
The decimal 5.937
ANSWER:
5.9375