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ElenaW [278]
3 years ago
10

Which is the graph of f(x) = (2)-x ?

Mathematics
1 answer:
Kay [80]3 years ago
6 0

Answer:Slope: −1

Y-Intercept: 2

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

Slope: −1

Y-Intercept: 2

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Alex wrote 103.903 in expanded form as 100+3x1+9x1/100+3x1/1,000 explain his mistake and how to correct it
11111nata11111 [884]
The 9 is in the tenths place so it should be 9x1/10. Meaning it would be 100+3x1+9x1/10+3x1,000
3 0
3 years ago
Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
3 years ago
Read 2 more answers
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
Evaluate the following expression (-3)^-2
OleMash [197]
<h3>Answer: the fraction 1/9</h3>

It is approximately equal to 0.1111

=================================

To get this answer, we use the rule

x^{-k} = \frac{1}{x^k}

The negative exponent tells us to apply the reciprocal to get the exponent to be positive.

So,

(-3)^{-2} = \frac{1}{(-3)^2}\\\\(-3)^{-2} = \frac{1}{9}

Squaring -3 means you square the negative as well

(-3)^2 = (-3)*(-3) = 9

8 0
2 years ago
Read 2 more answers
Which answer is an equation in point-slope form for the given point and slope?
astra-53 [7]

Answer:

the 3rd one


y - y1 = m(x - x1)

y- 1= 7(x +4)

4 0
3 years ago
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