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Paraphin [41]
3 years ago
9

Simplify the equation

ddle" class="latex-formula">
Mathematics
1 answer:
alexgriva [62]3 years ago
4 0
The answer is 3z. Hope this helped
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what is the area of a regular pentagon with sides of length 13 and an apothem of length 8.95, in square units
Assoli18 [71]
The area is 290.760680699535.
3 0
4 years ago
Please help easy and it is multiple choice
Step2247 [10]

5.702 cm

hoping this helps

5 0
3 years ago
Read 2 more answers
Clare has $150 in her bank account. She buys a bike for
Anastaziya [24]

Answer: $25

Step-by-step explanation:

150-200= -50

-50+75= 25

4 0
3 years ago
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Let f(x)= 7x-13.find f powered to the negative 1 power (x)
Reil [10]
Let f(x) be y so you have
y=7x-13
Reverse the signs of x and y so you have
x=7y-13
And then find the value of y
x+13=7y
(x+13)/7=y
And change y to f(x)-1
6 0
3 years ago
If (3-4i) (x+iy) = 3 root 5<br> show that x^2 + y^2=9/5
NNADVOKAT [17]

Answer:

the answer is 2 + i.

Step-by-step explanation:

Let the square root of 3 + 4i be x + iy.

So (x + iy) (x +iy) = 3 +4i

=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i

=> x^2 – y^2 + 2xyi = 3 + 4i

Equate the real and complex terms

=> x^2 - y^2 = 3 and 2xy = 4

2xy = 4

=> xy = 2

=> x = 2/y

Substitute in

=> x^2 - y^2 = 3

=> 4/y^2 - y^2 = 3

=> 4 – y^4 = 3y^2

=> y^4 + 3y^2 – 4 = 0

=> y^4 + 4y^2 – y^2 – 4 =0

=> y^2(y^2 + 4) – 1(y^2 + 4) =0

=> (y^2 – 1) (y^2 + 4) =0

Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.

Therefore y = 1 and x = 2/1 = 2

The required square root of 3 + 4i is 2 + i.

5 0
3 years ago
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