All categories

3 years ago

What is the common difference in the arithmetic sequence 10, 8, 6, 4, ...? 20pts

Mathematics

2 answers:

blagie [28]3 years ago

6 0

Answer:common difference is -2

Step-by-step explanation:

The sequence is arithmetic if the difference between consecutive terms is constant.

Dmitriy789 [7]3 years ago

3 0

Answer:common difference is -2

Step-by-step explanation:

You might be interested in

1. Find the Least Common Multiple of these two monomials: See picture

gtnhenbr [62]

Answer:

The last choice is correct

$LCM=120a^4b^7c^5$

Step-by-step explanation:

Least Common Multiple (LCM)

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

$12a^4b^2c^5$

$40a^3b^7c^1$

The prime factors of the first monomial are:

$2^2,3,a^4,b^2,c^5$

The prime factors of the second monomial are:

$2^3,5,a^3b^7c^1$

LCM = Multiply $2^3*3*5*a^4*b^7*c^5$

These are all the factors the greatest number of times they occur.

Operating:

$LCM=8*15*a^4*b^7*c^5$

$\boxed{LCM=120a^4b^7c^5}$

The last choice is correct

3 0

4 years ago

If f(x)=x^5-1 g(x)=5x^2 and h(x)=2x which expression is equivalent to [g*f*h](9)

vagabundo [1.1K]

F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x

Answer:
$\underbrace{5(\underbrace{(\underbrace{2\cdot9}_{h(9)})^5-1}_{f(g(9))})^2}_{g(f(h(9)))}$ $\boxed{C.}$

6 0

3 years ago

Which scatterplot shows the weakest negative linear correlation? Ed2020

Komok [63]

Answer:

the last one

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Bicycle license plates in Flatville each contain three letters. The first is chosen from the set ({C,H,L,P,R}) the second from (

amm1812

$5\cdot3\cdot4=60$ - the current possible number of plates

after adding 2 letters into the 1st set:
$7\cdot3\cdot4=82$
after adding 2 letters into the 2nd set:
$5\cdot5\cdot4=100$
after adding 2 letters into the 3rd set:
$5\cdot3\cdot6=90$
after adding 1 letter into the 1st set and 1 into the 2nd set:
$6\cdot4\cdot4=96$
after adding 1 letter into the 1st set and 1 into the 3rd set:
$6\cdot3\cdot5=90$
after adding 1 letter into the 2nd set and 1 into the 3rd set:
$5\cdot4\cdot4=80$

The largest possible number of plates after adding two numbers is 100.
So, the largest possible number of additional plates is 100-60=40

7 0

3 years ago

Help!!! f(x)=x+3 g(x) =7x+4

Tasya [4]

Answer:

8x+7

Step-by-step explanation:

8 0

3 years ago