All categories

3 years ago

How much interest is earned on $210 at 8% for 2 years? $3.60 $360 $410 $33.60

2 answers:

8 0

You would earn $33.60 of interest

Explanation: To find the interest you would multiply 210 by .08 (the percent in its decimal form) by 2 to get 33.60

Tpy6a [65]3 years ago

5 0

Answer:

$33.60

Step-by-step explanation:

Yearly interest is $16.80

You might be interested in

Three times the sum of a number and 4 is the same as 18 more than the number

11Alexandr11 [23.1K]

First, figure out what you do and don't know....
You do know that 3 times the sum of a number and 4 is 18 more than the number....you don't know the number so you make it the variable x
now take 3 times the sum of a number and 4 and make that an expression 3x+4 this expression is the same or equal to the sum of x and 18 x+18
3x+4=x+18
2x+4=18
2x=14
x=7
hope this helped :)

5 0

3 years ago

A stray dog ate 25 of your muffins that was 5/6 of all of them with how many did you start?

Maru [420]

Answer:

30 = total muffins

Step-by-step explanation:

To determine how many muffins were eaten, we take the total muffins times the fraction that were eaten

eaten muffins = total muffins * fraction

25 = total muffins* 5/6

Multiply each side by 6/5

6/5*25 = total muffins *5/6*6/5

30 = total muffins

3 0

3 years ago

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for

klio [65]

Answer:

The rate is $\frac{2}{5}$ degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose $\frac{1}{10}$ degree every $\frac{1}{4}$ hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every $\frac{1}{4}$ hour the temperature of a compound rose $\frac{1}{10}$ degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

$r=\dfrac{\frac{1}{10}}{\frac{1}{4}}$ degree

$r=\dfrac{4}{10}$ degree/hr

$r=\dfrac{2}{5}$ degree/hr

Therefore, the rate is $\frac{2}{5}$ degree per hour.

5 0

3 years ago

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

2 years ago

How do you solve 25n=70

alisha [4.7K]

You want to do to one side the same thing you do to the other side.

In order to get the n by itself you divide the 25n by 25. But in order to not change the answer you need to do the same to the 70.

$\frac{25n}{25} = \frac{70}{25}$

so n= $\frac{70}{25}$ which can be reduced to $\frac{14}{5}$

so n= $\frac{14}{5}$

5 0

3 years ago