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3 years ago

SYSTEM OF LINEAR EQUATIONS

Mathematics

2 answers:

olganol [36]3 years ago

8 0

Answer:

x = 10 y = -1

x = − 13/5 y = 7/5

x = -1 y = 3

Step-by-step explanation:

Effectus [21]3 years ago

4 0

Answer:

Step-by-step explanation:

x-y=11

2x+y=19

---------------

x=y+11

2(y+11)+y=19

2y+22+y=19

3y+22=19

3y=19-22

3y=-3

y=-3/3

y=-1

x-(-1)=11

x+1=11

x=11-1

x=10

Answer: x=10, y=-1. (10, -1).

-----------------------------------------

-6x+5y=1

6x+4y=-10

-------------------

9y=-9

y=-9/9

y=-1

6x+4(-1)=-10

6x-4=-10

6x=-10+4

6x=-6

x=-6/6

x=-1

Answer: x=-1, y=-1. (-1, -1).

------------------------------------

2x+9y=25

-4x-9y=-23

-------------------

-2x=2

x=2/-2

x=-1

2(-1)+9y=25

-2+9y=25

9y=25-(-2)

9y=25+2

9y=27

y=27/9

y=3

Answer: x=-1, y=3. (-1, 3).

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The loudest sound, measured in decibels, is calculated using the formula L=10 log, where L is the loudness, and I is the intensi

12345 [234]

The intensity of a fire alarm that measures 125 dB loud is 268,337.29

<h3>Formula and expressions</h3>

Given the expression L=10 logI

where;

L is the loudness
I is the intensity of the sound.

Given the following parameters

L = 125dB

Substitute the given parameters into the following

L=10 logI

125 = 10logI

logI = 125/10

logI = 12.5

I = e^12.5

I = 268,337.29

Hence the intensity of a fire alarm that measures 125 dB loud is 268,337.29

Learn more on subject of formula here: brainly.com/question/657646

7 0

2 years ago

Can you please help me

mixer [17]

Answer:

Step-by-step explanation:

cause both are congruent which means the same size if one has 14 why shouldnt the other too

3 0

3 years ago

Find the value of x in similar polygons below

muminat

Answer:

Choice A

Step-by-step explanation:

When you have two shapes that are similar their sides are always proportional. So all we have to do is set up a proportion.

$\frac{18}{4.5}=\frac{x}{1.5}$

Now we cross multiply and solve

$27=4.5x\\x=6$

And that's it x equals 6 feet.

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mamaluj [8]

I think its 201.333333333

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HACTEHA [7]

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