Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Veronica typically sells a
maximum of 30 pounds of berries but could also sell 10 pounds in the least.
Therefore, the PRACTICAL DOMAIN would be between 10 and 30 pounds of berries.
This can be expressed in terms of an inequality: 10 ≤ b ≤ 30 (i.e. all integers
between 10 and 30 inclusive).
If we were to be asked for the THEORETICAL
DOMAIN for the same function p(b)=5b−45. We would be considering the set of
logical values of b that would generate a reasonable output for the function. Clearly,
we could plausibly put any value of b in the function and still get a
reasonable output. So the theoretical domain of the function p(b)=5b−45 is the set of all real numbers.
Π = pi = 3.1415926 etc.
Circumference = diameter × π
We can rearrange this to show:
Diameter = circumference ÷ π
Diameter = 9.42 ÷ π
Diameter = 2.998 cm
The buttonhole should be around 3 cm.