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3 years ago

Why is Earth's outer core hotter than Earth's oceanic crust?

Mathematics

2 answers:

Brilliant_brown [7]3 years ago

8 0

Answer:

D earrhs outer cors is deeper within eafth than aceanic crust is

AlladinOne [14]3 years ago

8 0

Answer:

Step-by-step explanation:

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Manny bought a $1,980 snow thrower on the installment plan. The installment agreement included a 20% down payment and 12 monthly

melisa1 [442]

Step-by-step explanation:

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2 years ago

Da sofa is on sale for $98.60, which is 29% of the regular price. What is the regular price ?

yaroslaw [1]

Let the regular price be X
x\98.60 x 100=29%
100x\98.60=29(multiply both sides by 98.60 to remove the denominator
100x=2859.4(divide both sides by 100
x=28.594
regular price=$28.594

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2 years ago

What is the explicit formula for the nth term of a(n)=12a(n-1, where the 1st term is .001?

masya89 [10]

$\left\{\begin{array}{ccc}a_1=0.001\\a_n=12a_{n-1}\end{array}\right\\\\\boxed{a_n=0.001\cdot12^{n-1}}$

7 0

2 years ago

3 regions are defined in the figure find the volume generated by rotating the given region about the specific line

anastassius [24]

The volume generated by rotating the given region $R_{3}$ about OC is $\frac{4}{g} \pi$

<h3>Washer method</h3>

Because the given region ( $R_{3}$ ) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

$y=2(x)^{\frac{1}{4} }$

$x=(\frac{y}{2} )^{4}$

$y=2x$

$x=\frac{y}{2}$

$\int\limits^a_b {\pi } \, (R_{o^{2} } - R_{i^{2} } ) dy$

$R_{o} = x = \frac{y}{2}$

$R_{i} = x= (\frac{y}{2}) ^{4}$

$a=0, b=2$

$v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} ) dy$

$v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy$

$v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]$

$v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi$

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0

1 year ago

Find 15 percent of 15 percent of 15 percent of 500 how does this compare to finding 45 percent of 500?

4vir4ik [10]

Completely different...

.15*.15*.15*500

500(.15^3)=1.6875

500(.45)=225

4 0

2 years ago

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