Kennedy served 15 3 / 4 hours of volunteer service last month. She served 21 5 / 6 hours of volunteer service this month. How ma
1 answer:
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Answer:
There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days
Step-by-step explanation:
The given parameters are;
The half life of the radioactive substance = 45 days
The mass of the substance initially present = 6.2 grams
The expression for evaluating the half life is given as follows;
Where;
N(t) = The amount of the substance left after a given time period = 1 gram
N₀ = The initial amount of the radioactive substance = 6.2 grams
= The half life of the radioactive substance = 45 days
Substituting the values gives;
The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days
Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.
Answer:
D) y=x100+100x
Step-by-step explanation:
Answer a), b) and c) generates similar results for x 1
If x=1
Answers in a) b) and c) would be Y=100
But answer in d) would be Y=200
If x=2
Answers in a) b) and c) would be Y=200
But answer in d) would be Y=400