What is half of 1? Its from your bellybottom to your head.

Mathematics

2 answers:

Alexus [3.1K]2 years ago

6 0

Half of 1 is 1/2 or 0.5

ella [17]2 years ago

3 0

1 ÷ 2 = 1/2 ....anything to ask please pm me

You might be interested in

The average height of a 13 year old male in the U.S. is 60 inches, with a standard deviation of 2 inches. The average weight of

Romashka [77]

Since the average height is 60 inches and its deviation is 2 inches, one deviation to the right (or higher) is 62 inches (60 + 2). Two deviations is 64 inches, three deviations is 66 inches, and four deviations is 68 inches.

Since the average weight is 100 pounds and its deviation is 5 inches, we repeat the process from finding heights to get to 115 pounds. That takes three deviations.

The MORE deviations away, the more unusual it is. So the height (4 deviations) is more unusual than the weight (3 deviations).

5 0

2 years ago

Read 2 more answers

Can someone solve this for me?

Sav [38]

Answer:

Step-by-step explanation:

9 is 3/4*12.

3 0

2 years ago

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago

( HELP ASAP! EASY POINTS ) The picture below shows a box sliding down a ramp:

TEA [102]

Answer:

AC = 14 cosec(68)

Explanation:

Here given: