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Anna [14]
4 years ago
9

The probability that a person has a certain disease is 0.03. Medical diagnostic tests are available to determine whether the per

son actually has the disease. If the disease is actually​ present, the probability that the medical diagnostic test will give a positive result​ (indicating that the disease is​ present) is 0.92. Of the disease is not actually​ present, the probability of a positive test result​ (indicating that the disease is​ present) is 0.01. a. If the medical diagnostic test has given a positive result​ (indicating that the disease is​ present), what is the probability that the disease is actually​ present
Mathematics
1 answer:
Lina20 [59]4 years ago
7 0

Answer: 0.74

Step-by-step explanation:

A= "The person is sick "

B= "The test gives a positive result"

P(A)=0.03

P(B|A)=0.92

P(B|A')=0.01

P(A')=1-P(A)=1-0.03=0.97

P(B)=P(B|A)P(A)+P(B|A')P(A')=0.92*0.03+0.01*0.97=0.0373

Based in Bayes Rule

P(A|B)=P(B|A)P(A)/P(B)=0.92*0.03/0.0373=0.74

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El agua de una psicina alcanza 250 cm de altura. Si la estatura de pablo es 1520 mm dentro de la piscina sin que el agua lo cubr
Andrews [41]

Respuesta:

Pablo se cubrirá de agua si se para en la piscina

Explicación paso a paso:

El nivel del agua en la piscina = 250cm.

Altura de Pablo = 1520 mm

Para saber si pablo podría pararse en la piscina sin estar cubierto de agua, necesitamos determinar la altura de Pablo en centímetros.

Convertir la altura de Pablo de milímetro a centímetro;

1 mm hasta 0,1 cm

1520 mm = (1520 * 0,1) = 152 cm

Por lo tanto, pablo mide 152 cm.

Esto significa que la altura del agua en la piscina es mayor que la altura de Pablo y esto lo cubrirá el agua si se para en la piscina.

6 0
3 years ago
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

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\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

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3 years ago
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Natalka [10]
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3 0
3 years ago
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Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option
denis-greek [22]

Answer:

The probability that he teleports at least once a day =  \mathbf{\frac{5}{9}}

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = \frac{2}{3}

P( He not choose teleport in the evening ) = \frac{2}{3}

P ( he choose teleports at least once a day ) = 1 - P ( he not  choose teleports in a day )

                                                         = 1 - P( He not choose teleport in the morning ) \times P( He not choose teleport in the evening )

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                                           =  \frac{5}{9}

3 0
3 years ago
Franklin and Glennys are selling cases of chocolate bars for a school fundraiser. Franklin sells 5 cases and Glennys sells 8 cas
USPshnik [31]

Answer:

Franklin sold 5x bars.

Step-by-step explanation:

Franklin Sells 5x bars. I assume the question is asking for an expression with the usage of X instead of an actual value or when that is attainable. If there's any more information that you can provide, let me know and I'll redo the problem.

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3 years ago
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