A
(-2c-3d) (- 11) (- 2c-3d) (- 11) left parenthesis, minus, 2, c, minus, 3, d, right parenthesis, left parenthesis, minus, 11, right parenthesis
C
(66c + 99d) \ cdot \ dfrac {1} {3} (66c + 99d) ⋅ 3
1 left parenthesis, 66, c, plus, 99, d, right parenthesis, dot, start fraction, 1, divided by, 3, end fraction
<span> E
11\cdot(2c+3d)11⋅(2c+3d)11, dot, left parenthesis, 2, c, plus, 3, d, right parenthesis
</span> answer
(-2c-3d) (- 11) = 22c + 33d
(66c + 99d) * 1/3 = 22c + 33d
11 * ( 2c+3d) = 22c + 33d
Answer:
Answer:
The width of bookcase D is 61 cm
The width of bookcase E is 61 cm
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Sum the widths of the three bookcases A, B and C
step 2
Subtract the sum of the three bookcases A,B and C from the total length of the wall
step 3
Divide that answer in step 2 by 2, and that will let you know the widths of D and E, because they may have equal widths
therefore
The width of bookcase D is 61 cm
The width of bookcase E is 61 cm
Answer:
3842.5
Step-by-step explanation:
7685/2=3842.5
