Question

PLS Help me Error Analysis

Answer 1

we have

Pieces of mail delivered in December by the US postal service

$7.14*10^{10}$

Pieces of mail delivered in January by the US postal service

$3.21*10^{10}$

To find the total mail delivered for these two months, sum the two quantities

so

$7.14*10^{10}+3.21*10^{10}=(7.14+3.21)*10^{10}\\=10.35*10^{10} \\=(1.035*10)*10^{10} \\=1.035*(10* 10^{10})\\=1.035*10^{(10+1)} \\= 1.035*10^{11}$

therefore

the correct solution is $1.035*10^{11}$

the error is in this part

$10.35*10^{10}$

To move decimal over one place 10 to the power of 10 should be 10 to the power of 11

$1.035*10^{10}$