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inna [77]
3 years ago
13

Find the inverse of the following f(x)=-3x^2+3 X>0

Mathematics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer

f^-1(x) =√[(3-x)÷3]

Step-by-step explanation:

y=-3x^2+3

interchange 'y' with 'x'

x=-3y^2+3

make y the subject

3y^2=3-x

divide by '3' both sides

y^2=(3-x)÷3

apply square root both sides

√(y^2)=√[(3-x)÷3]

y=√[(3-x)÷3]

f^-1(x) =√[(3-x)÷3]

the inverse of the given function is

f^-1(x)=√[(3-x)÷3]

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Plz help.......................
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Read 2 more answers
(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

4 0
3 years ago
G two samples, one of size 14 and the second of size 13, are selected to test the difference between two population means. how m
vovikov84 [41]

Note :- If sample size n > 30 OR Population standard deviation σ is given then We use Z test.

If sample size n < 30 AND Population standard deviation σ is unknown then we use t test.

In this question we are not given Population standard deviations σ1 and σ2.

Also n1 = 14 and n2 = 13 both sample sizes are LESS than 30.

Therefore we use t test.

Given :- Assume the population standard deviations are equal. ( σ1 = σ2)

then Degrees of freedom = n1 + n2 - 2 = 14 + 13 - 2 = 25.

(kindly find the image attached with this solution)

Answer :- Therefore 25 degrees of freedom are used to find the t critical value.

5 0
3 years ago
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