Answer:
<h3>Part A</h3>
<u>4 CD's cost $30.40, so one CD costs:</u>
- 4p = $30.40
- p = $30.40/4
- p = $7.60
<h3>Part B</h3>
80% of the regular price is $7.60
<u>If the regular price is r, we have:</u>
- 0.8r = $7.60
- r = $7.60/0.8
- r = $9.5
<u>3 CD's at regular price cost:</u>
Since $25 < $28.5, we can't buy 3 more CD's.
<h3>Part C</h3>
Unfortunately, your problem statement appears to be incomplete. What distance are you talking about? Have you an illustration to share? How does 0.25 inches fit into this problem? Please try again. Double-check to ensure that you have shared all of the problem you wish to solve.
Answer:
hello!
the answer is :
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(1, 5/2)
Equation Form:
x = 1,y=
5/2
<h2 /><h2>
pls branliest! :)</h2>
One number is a, another one is b.
a+b=81
a-b=17
a+b+a-b=81+17
2a=98
a=49
b=32
So the two numbers are 49 and 32.
That's your answer.
